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Pavel [41]
2 years ago
9

What is the mass of 100 mL of corn oil?

Chemistry
1 answer:
prisoha [69]2 years ago
5 0

Answer:

m=(0.92g/ml)(100ml)

=92g

hope this helps

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Write down the needed and important water in our life?​
gizmo_the_mogwai [7]

Answer:

Because 60 percent of our body weight is made up of water. Our bodies use water in all the cells, organs, and tissues, to help regulate body temperature and maintain other bodily functions.

Explanation:

3 0
2 years ago
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If 14 moles of oxygen react with 14 moles of hydrogen to produce water, what is the
Leokris [45]
Hydrogen is the limiting reactant because when doing a stoichiometry equation for the reactants, hydrogen will be used completely by having a smaller yield and oxygen will be excess (7 moles to be exact)

7 0
2 years ago
A plant release it’s seed , but soon there after, the area seeds are in experiences a yearlong drought. How would the seeds most
SOVA2 [1]

Answer:

Plants will absorb water through their roots and release water as vapor into the air through these stomata. To survive in drought conditions, plants need to decrease transpiration to limit their water loss. Some plants that live in dry conditions have evolved to have smaller leaves and therefore fewer stomata.

Explanation:

Plants will absorb water through their roots and release water as vapor into the air through these stomata. To survive in drought conditions, plants need to decrease transpiration to limit their water loss. Some plants that live in dry conditions have evolved to have smaller leaves and therefore fewer stomata.

6 0
3 years ago
Calculate the theoretical carbonaceous and nitrogenous oxygen demand for:
serg [7]

Answer:

The correct answer is 129 mg and 232 mg.

Explanation:

Theoretical carbonaceous oxygen demand:

The reaction will be,  

C₂H₆O₂ + 5/2 O₂ ⇒ 2CO₂ + 3H₂O

Thus, for one mole of C₂H₆O₂ (ethylene glycol), 2.5 moles of O₂ is needed.  

The molecular mass of ethylene glycol is 62 grams per mole.  

The given mass of ethylene glycol is 100 mg or 0.1 grams

The moles of ethylene glycol will be,  

Moles = Weight/Molecular mass

= 0.1/62 = 1.613 × 10⁻³ mol

For 1.613 × 10⁻³ mol, the moles of O₂ will be,  

= 2.5×1.613×10⁻³

= 4.0.×10⁻³ × 32mol

= 0.129 grams or 129 mg.  

The theoretical nitrogenous oxygen demand is:  

The reaction will be,  

2NH₃-N + 9/2O₂ ⇒  4HNO2 + H₂O

Thus, for 2 moles of NH₃-N, 4.5 moles of O₂ is needed,  

Therefore, for 1 mol of NH₃-N, the oxygen required will be,  

= 4.5/2 = 2.25 mol

The given mass of NH₃-N is 100 mg, the moles of NH₃-N will be,  

Moles = 100×10⁻³/31 = 3.225 × 10⁻³ mol (The molecular mass of NH₃-N is 31 gram per mole)

The moles of O₂ is 2.25 × 3.225 × 10⁻³ = 7.258 × 10⁻³ mol.  

Now the mass of O2 will be,  

= 7.258 × 10⁻³ × 32

= 0.232 grams

= 232 mg

5 0
2 years ago
10 pts) A student titrates a 20.00 mL sample of an aqueous borax solution with 1.03 M H2SO4. If 2.07 mL of acid are needed to re
Natasha2012 [34]

Answer: The molarity of the borax solution is 0.107 M

Explanation:

The neutralization reaction is:

Na_2B_4O_7.10H_2O+H_2SO_4(aq)\rightarrow Na_2SO_4+4H_3BO_3+5H_2O

According to neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of H_2SO_4 = 2

n_2 = acidity of borax = 2

M_1 = concentration of H_2SO_4 = 1.03 M

M_2 = concentration of borax =?

V_1 = volume of H_2SO_4  = 2.07ml

V_2 = volume of borax = 20.0 ml

Now put all the given values in the above law, we get the molarity of borax:

(2\times 1.03\times 2.07)=(2\times M_2\times 20.0)

By solving the terms, we get :

M_2=0.107M

Thus the molarity of the borax solution is 0.107 M

7 0
3 years ago
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