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aksik [14]
3 years ago
9

Students at Lincoln middle school earn $5 for every 4 boxes of cookie dough sold during a fundraiser. Students at Williams middl

e school earn $7 for every 6 rolls of wrapping paper
Mathematics
2 answers:
muminat3 years ago
7 0

Answer:

5x4 = 20

7x6=42

Anvisha [2.4K]3 years ago
5 0

Answer:

5 and 4

7 and 6

Step-by-step explanation:

what is the question

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NEED HELP! DUE IN 1 HOUR PLEASE
Alenkasestr [34]

Answer:

Step-by-step explanation

if my answer is wrong i'm sorry here is a manual on how to do it if its wrong

i think they are right but just in case

Identify the output values. If each input value leads to only one output value, classify the relationship as a function. If any input value leads to two or more outputs, do not classify the relationship as a function.

1 relation

2 function

3 relation

4 function

i know 4 is right but i don't know about others double check i suggest just in case i think they are right

6 0
3 years ago
The 4th tetm of a G.P. is 54 and the 6th term is 24. Is 64/9 a term of the G.p.?​
julsineya [31]

Answer:

d

Step-by-step explanation:

6 0
3 years ago
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There are some red and blue balls in a bag of 21 balls and the probability of picking 2 red balls out in a row is 1/14 how many
Over [174]

Answer:

6 red balls

Step-by-step explanation:

The probability in the first pick

6/21

The probability in the second pick (without replacement)

5/20

the requested probability

(6/21)(5/20) = 30/420

simplification

30/420 = 3/42 = 1/14

Hope this helps

8 0
2 years ago
Read 2 more answers
The joint probability mass function of XX and YY is given by p(1,1)=0p(2,1)=0.1p(3,1)=0.05p(1,2)=0.05p(2,2)=0.3p(3,2)=0.1p(1,3)=
inessss [21]

Answer:

P(Y=1|X=3)=0.125

Step-by-step explanation:

Given :

p(1,1)=0  

p(2,1)=0.1

p(3,1)=0.05

p(1,2)=0.05

p(2,2)=0.3

p(3,2)=0.1

p(1,3)=0.05

p(2,3)=0.1

p(3,3)=0.25

Now we are supposed to find the conditional mass function of Y given X=3 :  P(Y=1|X=3)

P(X=3) = P(X=3,Y=1)+P(X=3,Y=2) +P(X=3,Y=3)

P(X=3)=p(3,1) +p(3,2) +p(3,3)

P(X=3)=0.05+0.1+0.25=0.4

P(Y=1|X=3)=\frac{P(X=3,Y=1)}{P(X=3)} =\frac{p(3,1)}{P(X=3)}=\frac{0.05}{0.4}= 0.125

Hence P(Y=1|X=3)=0.125

8 0
3 years ago
Two non-simultaneous events have an equal likelihood of occurring (50%). If the events are independent of each other, what is th
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3 years ago
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