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3 years ago

Solve for x pls show work 1/2*(x - -6)= -1

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

5 0

Answer: x = -4

Step-by-step explanation:

1/2 * (x - (-6)) = 1

distribute

1/2x + 3 = 1

isolate the variable

1/2x = -2

x = - 4

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Please and thank you help me

Leona [35]

Answer:

y = 3x - 5

Step-by-step explanation:

y = mx + b

m (slope) = 3/1 or 3

b (y-intercept) = -5

y = 3x - 5

8 0

2 years ago

Find the measure of <_A. (show work if possible).

Sholpan [36]

Answer:

We know that exterior angle of a triangle is equal to the sum of two opposite interior angle.

Step-by-step explanation:

<A = 4y

< B = 3y + 6°

<BCD = 111°

Now

<BCD = <A + <B( exterior angle of a triangle is equal to the sum of two opposite interior angle)

111° = 4y + 3y + 6°

111° - 6° = 7y

105° =7y

Therefore y = 15°

The measure of <A = 4*15°= 60°

4 0

3 years ago

in 2019 there were 16 named storms, of which 8 grew into hurricanes and 5 were major. What fraction of hurricanes were major?

olga2289 [7]

There were 16 total storms, meaning our denominator is 16. Since 8 grew into hurricanes, we can leave that alone. Since 5 out of 16 storms were major, 5 is our numerator.

5/16 storms were major because 8 were hurricanes and the other 3 were other kinds of storms. As a decimal conversion, about 31% of these storms were major.

How to find the percentage conversion:

Step 1: We take the fraction 5/16.

Step 2: Since our numerator is 5 and the default denominator is a maximum of 100, we can multiply 5 by 100.

5 x 100 = 500

Step 3: We can divide 100 by 16 to get our decimal conversion.

100 divided by 16 will give us 31.25, which also is representative of 31 and 1/4 added together.

Your final answer: With there being 16 storms, 5 of these storms are major (5/16). In terms of if there were 100 total storms, about 3/10 of these storms were major.

6 0

2 years ago

4. Subtract: 8-4 1/2. O A. 4 1/2 O B. 3 O C. 3 1/2 O D. 4

LekaFEV [45]

Answer:

A) 4 1/2

Step-by-step explanation:

8 - 4 1 / 2

4 1 / 2

= 4 1 / 2

3 0

2 years ago

Read 2 more answers

A common way for two people to settle a frivolous dispute is to play a game of rock-paper-scissors. In this game, each person si

Leokris [45]

Answer:

(a) P(A) = 0.34

(b) P(B) = 0.33

(c) P(C) = 0.33

(d) The Complement of event A = 1 - P(A) = 0.66

Step-by-step explanation:

We are given that in the long run, roommate A chooses rock 36% of the time, and roommate B chooses rock 22% of the time; roommate A selects paper 32% of the time, and roommate B selects paper 25% of the time; roommate A chooses scissors 32% of the time, and roommate B chooses scissors 53% of the time.

Let the probability that roommate A chooses rock = P( $R_A$ ) = 0.36

The probability that roommate A chooses paper = P( $P_A$ ) = 0.32

The probability that roommate A chooses scissors = P( $S_A$ ) = 0.32

The probability that roommate B chooses rock = P( $R_B$ ) = 0.22

The probability that roommate B chooses paper = P( $P_B$ ) = 0.25

The probability that roommate B chooses scissors = P( $S_B$ ) = 0.53

(a) Let A = event that roommate A wins the game and thus does not have to wash the dishes.

This will happen only when roommate A chooses rock and roommate B chooses scissors or roommate A chooses paper and roommate B chooses rock or roommate A chooses scissors and roommate B chooses paper.

So, P(A) = $P(R_A) \times P(S_B) + P(P_A) \times P(R_B) + P(S_A) \times P(P_B)$

= (0.36 $\times$ 0.53) + (0.32 $\times$ 0.22) + (0.32 $\times$ 0.25)

= 0.1908 + 0.0704 + 0.08

P(A) = 0.34

(b) Let B = event that roommate B wins the game and thus does not have to wash the dishes.

This will happen only when roommate B chooses rock and roommate A chooses scissors or roommate B chooses paper and roommate A chooses rock or roommate B chooses scissors and roommate A chooses paper.

So, P(B) = $P(R_B) \times P(S_A) + P(P_B) \times P(R_A) + P(S_B) \times P(P_A)$

= (0.22 $\times$ 0.32) + (0.25 $\times$ 0.36) + (0.53 $\times$ 0.32)

= 0.0704 + 0.09 + 0.1696

P(B) = 0.33

(c) Let C = event that the game ends in a tie.

This will happen only when roommate A chooses rock and roommate B also chooses rock or roommate A chooses paper and roommate B also chooses paper or roommate A chooses scissors and roommate B also chooses scissors.

So, P(C) = $P(R_A) \times P(R_B) + P(P_A) \times P(P_B) + P(S_A) \times P(S_B)$

= (0.36 $\times$ 0.22) + (0.32 $\times$ 0.25) + (0.32 $\times$ 0.53)

= 0.0792 + 0.08 + 0.1696

P(C) = 0.3288 ≈ 0.33

(d) The complement of event A = P(A') = 1 - P(A)

= 1 - 0.34 = 0.66.

4 0

3 years ago