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3 years ago

Bubbles in soda rise to the surface. Explain this in terms of density.

Chemistry

1 answer:

algol [13]3 years ago

7 0

Answer:

Bubbles are comprised of gases, which have a lesser density than water. Since they are less dense, they get pushed up to the surface, and they rise, lighter than the liquid around them. This is just like helium in air; helium is lighter than air, so it rises, pushed to the top by the pressure around it.

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A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi

tester [92]

Answer:

V₁ = 374.71 mL

Explanation:

Given data:

Initial volume of gas= ?

Initial temperature = 22°C

Final temperature = 86°C

Final volume = 456 mL

Solution:

Initial temperature = 22°C (22+273 = 295 k)

Final temperature = 86°C (86+273 = 359 k)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₁ = 456 mL × 295 K / 359 k

V₁ = 134520 mL.K / 359 k

V₁ = 374.71 mL

3 0

3 years ago

A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t

777dan777 [17]

The molar extinction coefficient is 15,200 $M^{-1} cm^{-1}$ .

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = $\frac{A}{cl}$

ξ = $\frac{1.140}{1.5*10^{-4}*0.5 }$

Performing multiplication in denominator to find the value of molar extinction coefficient

ξ = $\frac{1.140}{0.000075}$

Performing division to find the value of molar extinction coefficient

ξ = 15,200 $M^{-1} cm^{-1}$

Hence, the molar extinction coefficient is 15,200 $M^{-1} cm^{-1}$ .

Learn more about molar extinction coefficient -

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1 year ago

Why it is advisided to freshly prepare the ferrous sulphate solution for experiment

chubhunter [2.5K]

Here is a site my buddie has to help you. Well co-owner..
https://www.quora.com/Why-is-fresly-prepared-FeSO4-required-for-the-ring-test

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3 years ago

Which lists mixtures, in order, from the smallest particles to the largest particles?

Kisachek [45]

Answer:

A. Solution, Colloid, Suspension

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3 years ago

What is the mass percent of nitrogen in: 1. N2O 2. NO 3. NO2 4. N2O2

Temka [501]

We’re going to use the mass percent formula shown below:

For the percent by mass N, we’re going to rewrite the equation as:

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Problem Details
Calculate the mass percent composition of nitrogen in each nitrogen-containing compound:

c. NO2

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2 years ago