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Novosadov [1.4K]
3 years ago
12

How many formula units make up 16.4 g of magnesium chloride (MgCl2)?

Chemistry
2 answers:
Svetach [21]3 years ago
8 0

<span>molar mass of MgCl2  = 24.32 + 2 x (35.45) = 95.22 g</span><span>

<span>16.4g MgCl2 x (1 mol MgCl2/95.22 g MgCl2) = 0.172 mol MgCl2 </span>
 </span>
<span>0.172 mol MgCl2 x (6.022 x 10^23/1 mol MgCl2) = 10.36 x 10^22 atoms<span> </span></span>

tamaranim1 [39]3 years ago
8 0

<u>Answer:</u> The number of formula units in the given amount of magnesium chloride is 1.0357\times 10^{23}

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of magnesium chloride = 16.4 g

Molar mass of magnesium chloride = 95.2 g/mol

Putting values in above equation, we get:

\text{Moles of }MgCl_2=\frac{16.4g}{95.2g/mol}=0.172mol

Formula units is defined as lowest whole number ratio of ions in an ionic compound. It is calculated by multiplying the number of moles by Avogadro's number which is 6.022\times 10^{23}

We are given:

Number of moles of magnesium chloride = 0.172 moles

Number of formula units = 0.172\times 6.022\times 10^{23}=1.0357\times 10^{23}

Hence, the number of formula units in the given amount of magnesium chloride is 1.0357\times 10^{23}

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