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sweet-ann [11.9K]
3 years ago
5

Could someone please help answer this (homework help) will give brainliest, thank u!

Mathematics
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

T= 1.29k

Step-by-step explanation:

T= total price which is an independent variable

? kgs since we dont know how many kilograms she will buy.

k = number of kilograms of food

Each kilos costs is 1.29

T= 1.29k

You might be interested in
Figure abcd is parallelogram. What are measures of B and D?
nika2105 [10]

Answer:

Both are 55

Step-by-step explanation:

To solve this problem, set the equations equal to each other, solve for n, then plug in the values

Solve for n:

1. 2n+15=3n-5

2. Add 5 to both sides

3. Now you have 2n+20=3n

4. Subtract 2n from both sides

5. You are left with n=20

Next, plug it in:

1. Replace all n's with 20

2. 2(20)+15=55

3. 3(20)-5=55

There you go! Hope this helps!

3 0
3 years ago
Solve for x by factoring sqrt{x+7}=x+5
Vlada [557]

Answer:x=-3

Step-by-step explanation:

Factor and set each factor equal to zero.

8 0
3 years ago
Use the quadratic formula to solve each equation.
Elden [556K]

Answer:

1) x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}

x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}

2) x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}

x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}

3) p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}

p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}

4) y_1 = \frac{-3 - 9}{4}=-3

y_2 = \frac{-3 + 9}{4}= \frac{3}{2}

Step-by-step explanation:

The quadratic formula is given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

We can use this formula in order to solve the following equations:

1. x^2 − 2x = 12 → a = 1, b = −2, c = −12

For this case if we apply the quadratic formula we got:

x = \frac{-(-2) \pm \sqrt{(-2)^2 -4(1)(-12)}}{2(1)}

x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}

x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}

2. 1/2x^2 − 6x = 2 → a = 1 / 2, b = −6, c = −2

For this case if we apply the quadratic formula we got:

x = \frac{-(-6) \pm \sqrt{(-6)^2 -4(1/2)(-2)}}{2(1/2)}

x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}

x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}

3. 2p^2 + 8p = 7 → a = 2, b = 8, c = −7

For this case if we apply the quadratic formula we got:

p = \frac{-(8) \pm \sqrt{(8)^2 -4(2)(-7)}}{2(2)}

p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}

p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}

4. 2y^2 + 3y − 5 = 4 → a = 2, b = 3, c = −9

For this case if we apply the quadratic formula we got:

y = \frac{-(3) \pm \sqrt{(3)^2 -4(2)(-9)}}{2(2)}

y_1 = \frac{-3 - 9}{4}=-3

y_2 = \frac{-3 + 9}{4}= \frac{3}{2}

8 0
4 years ago
PLEASE HELP ME IS DUE TMW! Plz :)
trapecia [35]

What do the instructions say?

4 0
4 years ago
Solve for y.
Svetradugi [14.3K]
1. For y, I think that refers to the first picture attached. As you can see, each side of the triangle have the same short line drawn across it. It means that they are equal in length. That means the triangle is equilateral, which means each interior angle is 60°. Thus,

60 = 5y + 10
5y = 60 - 10
5y = 50
y = 50/5 =<em> 10</em>

2. As you can see in the second picture attached, Angles B and C are equal. That also means that their respective opposite sides are equal. So,

8x - 4 = 5x + 11
8x - 5x = 11 + 4
3x = 15
x = 15/3 = 5

Consequently,
BC = 4x - 2
BC = 4(5) - 2 = <em>18</em>
4 0
4 years ago
Read 2 more answers
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