Answer:
Coefficient of friction = 0.836
Explanation:
If v be the speed after one quarter of the circular path
v² = 2as = 2 x 1.85 x 2πr/4 ; v²/r = 1.85 x 3.14 = 5.8
tangential acceleration = 5.8 m/s²
radial acceleration = v² /r = 5.8
total acceleration = √2 x 5.8
m x√2 x 5.8 = m x g xμ
μ = √2 x 5.8 / 9.8 = 0.836
Answer:
Explanation:
Given
Cross-sectional area of two areas is


It is filled with oil of density 
mass of car place on Large area 
Suppose a mass of m kg is placed on smaller area
According to pascal law's intensity of pressure is same at every point on Liquid




Distance is how far something moves in a specific amount of time.
The student that measured the mass to be 16110g got closest to the known result. She is off by 10 g.