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2 years ago

Can inserting a resistor in a circuit produce an effect similar to a short circuit?

Physics

1 answer:

tresset_1 [31]2 years ago

6 0

Answer:

By ‘inserting’ you means to putting a resistor in series. In this case, no, there is no resistance that would produce the same effect as a short circuit.

If you adding a resistor in parallel with the circuit, then if it had a low value It might be similar to a short circuit. I

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Which phrase does not describe a mineral?

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The answer is A) specific chemical consumption

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3 years ago

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A proposed answer to a scientific problem is a _.

liubo4ka [24]

Answer:

A proposed answer to a s scientific problem is a hypothesis.

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3 years ago

Can anyone help me with this please

Anastasy [175]

Answer:

1270 J

Explanation:

Recall that the mechanical energy of a system is the addition of the Potential energy and the Kinetic energy at any given time.

As the skier descends, potential energy is converted into kinetic energy, but the total mechanical energy should remain the same.

We see that it is not the case, so that difference is what has gone into thermal energy; 19500 J - 18230 J = 1270 J

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3 years ago

Water, which we can treat as ideal and incompressible, flows at 12 m/s in a horizontal pipe with a pressure of 3.0 × 10^4 Pa.

Triss [41]

Answer:

9.8 × 10⁴Pa

Explanation:

Given:

Velocity V₁ = 12m/s

Pressure P₁ = 3 × 10⁴ Pa

From continuity equation we have

ρA₁V₁ = ρA₂V₂

A₁V₁ = A₂V₂

making V₂ the subject of the equation;

$V_{2} = \frac{A_{1}V_{1}}{A_{2}}$

the pipe is widened to twice its original radius,

r₂ = 2r₁

then the cross-sectional area A₂ = 4A₁

⇒ $V_{2}= \frac{A_{1}V_{1}}{4A_{1}}$

$V_{2}= \frac{V_{1}}{4}$

This implies that the water speed will drop by a factor of $\frac{1}{4}$ because of the increase the pipe cross-sectional area.

The Bernoulli Equation;

Energy per unit volume before = Energy per unit volume after

p₁ + $\frac{1}{2}$ ρV₁² + ρgh₁ = p₂ + $\frac{1}{2}$ ρV₂² + ρgh₂

Total pressure is constant and $P_{T}$ = P = $\frac{1}{2}$ ρV₂²ρV²

p₁ + $\frac{1}{2}$ ρV₁² = p₂ + $\frac{1}{2}$ ρV₂²

Making p₂ the subject of the equation above;

p₂ = p₁ + $\frac{1}{2}$ ρV₁² - $\frac{1}{2}$ ρV₂²

But $V_{2} = \frac{V_{1}}{4}$ so,

p₂ = p₁ + $\frac{1}{2}$ ρV₁² - $\frac{1}{2}$ ρ $\frac{V_{1}^{2}}{4^{2}}$

p₂ = 3.0 x 10⁴ + ( $\frac{1}{2}$ × 1000 × 12²) - ( $\frac{1}{2}$ × 1000 × 12²/4² )

P₂ = 3.0 x 10⁴ + 7.2 × 10⁴ - 4.05 x 10³

P₂ = 9.79 × 10⁴Pa

P₂ = 9.8 × 10⁴Pa

4 0

3 years ago

A car can accelerate from rest to 28 m/s and travels 280meters. How long does this acceleration take?

Reika [66]

Answer:

$a=1.4m/s^2$

Explanation:

From the question we are told that

Velocity v=28m/s

Distance d=280

Generally the Newtons equation for motion is mathematically given as

Acceleration

$v^2=2as$

$a=\frac{V^2}{2s}$

$a=\frac{28^2}{2*280}$

$a=1.4m/s^2$

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3 years ago