Answer:
Resistance of gold wire, 
Explanation:
In this question we have given
Density of gold, 
resistivity of gold, 
Length of wire, 
Temperature, 
We know that relation between volume and density is given as

Therefore, volume occupied by one gram gold is given as,
.........(1)
We Know that Volume of gold wire which is cylindrical in shape is given by following formula
......(2)
Here,
...........(3)
here A is the cross sectional area of cylendrical gold wire
From equation 2 and 3
we got
...............(4)
on comparing equation 1 and equation 4, we got,



we know that resistance and resistivity are related by following formula,
................(5)
Put values of resistivity, A and L in equation 5, we got


Therefore resistance of gold wire, 
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Answer:
I think B.The outer,middle and inner ear
Cells membrain cellwall glucose for a leaf
Answer:
The wavelength of the standing wave is 3 m.
Explanation:
Given that,
Length = 6 m
Nodes = 4
We need to calculate the wave length
Using formula of nodes


Where, l = length
n = number of nodes
= wavelength
Put the value into the formula


Hence, The wavelength of the standing wave is 3 m.