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baherus [9]
3 years ago
15

A student in an undergraduate physics lab is studying Archimede's principle of bouyancy. The student is given a brass cylinder a

nd, using a triple beam balance, finds the mass to be 3.21 kg. The density of this particular alloy of brass is 8.62 g/cm 3 . The student ties a massless string to one end of the cylinder and submerges it into a tank of water where there is an apparent reduction in the weight of the cylinder. With this information, calculate the volume, V , of the cylinder and the tension, T , in the string when it is submerged in the tank of water. The density of water is 1.00 g/cm 3 , and the acceleration due to gravity is gVolume of the cylinder: _____ cm3Tension in the string: ______ N
Physics
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:

V = 0.3724 m³

T = 27.836 N

Explanation:

Given :

m = 3.21 kg  , W= 3.21 * 9.81 m / s² = 31.4901 N

ρ = 8.62 g / cm ³  = 8620 kg / m³

V = m / ρ =  3.21 kg  /  8620 kg / m³

V = 0.3724 m³

when submerged the weight of brass cylinder is equal to the tension in string:

F =  (0.3724m³) * (1000 kg / m³) * (9.81 m/s²²) = 3.653 ≈ 3.65 N

T = 31.4901 N - 3.65 N  

T = 27.836 N

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Darya [45]

To answer the two questions, we need to know two important equations involving centripetal movement:

v = ωr (ω represents angular velocity <u>in radians</u>)

a = \frac{v^{2}}{r}

Let's apply the first equation to question a:

v = ωr

v = ((1800*2π) / 60) * 0.26

Wait. 2π? 0.26? 60? Let's break down why these numbers are written differently. In order to use the equation v = ωr, it is important that the units of ω is in radians. Since one revolution is equivalent to 2π radians, we can easily do the conversion from revolutions to radians by multiplying it by 2π. As for 0.26, note that the question asks for the units to be m/s. Since we need meters, we simply convert 26 cm, our radius, into meters. The revolutions is also given in revs/min, and we need to convert it into revs/sec so that we can get our final units correct. As a result, we divide the rate by 60 to convert minutes into seconds.

Back to the equation:

v = ((1800*2π)/60) * 0.26

v = (1800*2(3.14)/60) * 0.26

v = (11304/60) * 0.26

v = 188.4 * 0.26

v = 48.984

v = 49 (m/s)

Now that we know the linear velocity, we can find the centripetal acceleration:

a = \frac{v^{2}}{r}

a = \frac{49^{2}}{0.26}

a = 9234.6 (m/s^{2})

Wow! That's fast!

<u>We now have our answers for a and b:</u>

a. 49 (m/s)

b. 9.2 * 10^{3} (m/s^{2})

If you have any questions on how I got to these answers, just ask!

- breezyツ

5 0
2 years ago
A telephone line has a signal-to-noise ratio of 1000 and a bandwidth of 4 KHz. What is the maximum data rate supported by this l
ivolga24 [154]

Answer:

The maximum data rate supported by this line is 39900 bps

Explanation:

The maximum data rate supported by this line can be obtained using the formula below

c = W*log2(S/N+1)

where;

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W is the bandwidth = 4kHz

S/N+1 is the signal to noise ratio = 1001

c = 4*log2(1001)

c = 39868.9 ≅ 39900 bps

Therefore, the maximum data rate supported by this line is 39900 bps

5 0
3 years ago
A race car accelerates on a straight road from rest to speed of 180 km/hr in 25s . Assuming uniform acceleration of the car thro
adelina 88 [10]
X-x0=0.5(v0+v)t ergo x=0.5(50)25=625m
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3 years ago
Imagine that you are sitting in a chamber with your back to one wall. An electron beam, moving horizontally from the front wall
Allisa [31]

Answer:

Flemmings' left hand rule  and Downward direction

Explanation:

The person could able to determine the path of force by applying the left-hand rule of Fleming.

Via holding the thumb the forefinger and second finger at right angles for one other

The left-hand rule is applied in the electric motors

On the other hand, the right-hand rule is applied for electric generators.

So different hands are used for the different thing as there is a difference between the cause and effect

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7 0
3 years ago
James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.
belka [17]

a. The most momentum is attained by James.

b. The resultant force acting on her is 90.77N.

c. Time taken for him to stop is  3.24 s

<h3>What is momentum?</h3>

Momentum of any object is the product of the velocity of the object and its mass.

P =mv

James has a mass of 98 kg and Basma has a mass of 59 kg. James is running at 3.0 m/s, while Basma is running at 4.0 m/s.

a.

Substitute the values, we get

P jane= 98 kg x 3

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P Basma = 59 kg x 4

P Basma = 236  kg.m/s

Therefore, the momentum is large for James.

b. Basma approaches a road, so she stops quickly. It takes her 2.6 seconds to stop. The resultant force acting on her

F. t = P Basma

F =[ 236/2.6

F = 90.77 N

Thus, the resultant force on Basma is 90.77 N.

c. James also stops for the road. If he were to have the same resultant force acting on him, Time taken for him to stop is

F = 90.77 = P james/t

t = 294 / 90.77

t = 3.24 s

Thus, time taken for James to stop for the same resultant force is  3.24 s

Learn more about momentum.

brainly.com/question/4956182

#SPJ1

5 0
1 year ago
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