1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sedaia [141]
2 years ago
7

18 kilogram Mass Blokus addressed a level surface if the coefficient of static friction between the Block in the surface is 0.6

what is horizontal force is required to take gravity 10m/s2
​
Physics
1 answer:
Tasya [4]2 years ago
4 0

Question: 18 kilogram Mass Block rest on level surface if the coefficient of static friction between the Block and the surface is 0.6 what  horizontal force is required to just move the blcok ( take gravity as 10m/s2 )

Answer:

108 N

Explanation:

From the question,

Applying

F' = mgμ................ Equation 1

Where F' = Frictional force = horizontal  force required to just move the block,  m = mass of the block, g = acceleration due to gravity, μ = coefficient of static friction.

From the question,

Given: m = 18 kg, μ = 0.6, g = 10 m/s²

Substitute these values into equation 1

F' = 18×0.6×10

F' = 108 N

You might be interested in
What would occur if the index of refraction of a material was less than n=1?
Bingel [31]

The correct answer is (A). The speed of light would increase to a speed larger than the maximum speed of light in vacuum.

The index of refraction is the ratio of speed of light in vacuum to the speed of light in a medium.

n=C/V

here, n is the index of refraction, c the speed of light in vacuum, v is speed of light in any medium.

Now if the value of index of refraction is less than one, than the value of speed of light would be greater than the speed of light in the vacuum.


3 0
3 years ago
Read 2 more answers
Three people pull simultaneously on a stubborn donkey. jack pulls eastward with a force of 92.5 n, jill pulls with 89.9 n in the
alekssr [168]
Jack------------ force of 92.5 n   eastward-------Fjack(X)=92.5 n   Fjack(Y)=0

<span>jill ------------------------------- force of 89.9 n   northeast
Fjill(X)=cos45*89.9=63.57 n
</span>Fjill(Y)=sin45*89.9=63.57 n<span>

</span>jane -----------------------------force of 163 n   southeast
Fjane(X)=cos45*163=115.26 n
Fjane(X)=-sin45*163=-115.26 n

Ftotal (X)=92.5+63.57+115.26=271.33 n
Ftotal (Y)=0+63.57-115.26=-51.69 n

Fotal=((271.33)^2+(-115.26)^2) ^0.5=294.80 n southeast

the magnitude of the net force the people exert on the donkey. is 294.80 n southeast
7 0
3 years ago
The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the
PIT_PIT [208]

The drag force is directly proportional to the square of the velocity of motion of the object. So as the speed is doubled, the magnitude of drag force will get quadrupled.

<u>Explanation: </u>

Drag force is the opposing or resisting force acting on any object by the medium in which it is moving. So in this case, you are riding a bicycle, thus the medium can be considered as air.

The formula for calculating drag force is as below:

               \text {Drag force }=\frac{1}{2} \rho v^{2} C_{D} A

Here, ρ is the density of the air molecules, v is the velocity or speed of the bicycle, CD is the drag coefficient and A is the area of the bicycle.

In the above equation, only the term velocity will be a varying quantity with respect to time and other quantities will remain constant throughout the single situation of riding of bicycle.

So, the equation can be,

             \text { Drag force }=k v^{2}

Where ,  

     k=\frac{1}{2} \rho C_{D} A (constant for this whole condition)

Now given the speed of bicycle increased from v to 2v, so the initial drag force will be

                   N_{i}=k v^{2}

After increase in speed, the final drag force will be  

                   N_{f}=k(2 v)^{2}

                   N_{f}=4 k v^{2}=4 N_{i}

Thus, if the speed of the bicycle is doubled, the drag force will get increased by four times.

4 0
3 years ago
Every force has a specific and identifiable cause called a(n)...............
goblinko [34]
1 Bc I just did it and got it right
8 0
2 years ago
You have arrived at the scene of a two car accident. You know the following pieces of information:
Pani-rosa [81]

The initial velocity of car 1 is 20 m/s to the right

The initial velocity of car 2 is zero

The final velocity of car 2 is 10 m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision.

Therefore, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 2000 kg is the mass of the first car

u_1 is the initial velocity of the first car

v_1 = 10 m/s is the final velocity of the first car (taking right as positive direction)

m_2 = 2000 kg is the mass of the second car

u_2 = 0 is the initial velocity of the second car

v_2 is the final velocity of the second car

We also know the initial momentum of car 1, which is

p_1 =40,000 kg m/s

And since momentum is the mass times the velocity, we find the initial velocity of car 1:

u_1 = \frac{p_1}{m_1}=\frac{40,000}{2,000}=20 m/s

with a positive sign, since the direction is to the right.

Now we can re-arrange the previous equation and solve for v2, the final velocity of car 2:

v_2 = \frac{m_1 u_1 -m_1 v_1}{m_2} = \frac{(2000)(20)-(2000)(10)}{2000}=10 m/s

And since the sign is positive, the direction is the same as the initial direction of car 1, so to the right.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

8 0
3 years ago
Other questions:
  • What causes a material to be classified as ferromagnetic?
    13·1 answer
  • Rank the tensions in the ropes, t1, t2, and t3, from smallest to largest, when the boxes are in motion and there is no friction
    13·1 answer
  • A pendulum oscillates 50 times in 6 seconds. Find its time period and frequency? ​
    6·1 answer
  • Please help! you are amazing! brainliest!
    11·2 answers
  • What's at the bottom of the black hole? Explain .​
    5·1 answer
  • A 3.50-g bullet has a muzzle velocity of 250 m/s when fired by a rifle with a weight of 25.0 N. (a) Determine the recoil speed o
    12·1 answer
  • Rubric for Grading O Activity3. Answer me! Directions: Compare and contrast the scientific method in philosophy and in science.
    15·1 answer
  • Inertia causes bodies to slow in their motion, unless they’re pushed by a force.
    12·1 answer
  • Calculate the pressure on a man’s foot when a woman of mass 65 kg steps on his foot with her heel which has an area of 0.12m2 wi
    13·1 answer
  • What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!