Answer:
a) 39.6 m/s b) 4123 N
Explanation:
a) At the top of the loop, all of the forces point downwards (force of gravity and normal force).
Fnet=ma
ma=m(v^2/R) (centripetal acceleration)
mg=m(v^2/R)
m cancels out (this is why pilot feels weightless) so,
g=(v^2/R)
9.8 m/s^2 = v^2/160 m
v^2=1568 m^2/s^2
v=39.6 m/s
b) At the bottom of the loop, the normal force and the force of gravity point in opposite directions. The normal force is the weight felt.
Convert 300 km/hr to m/s
300 km/hr=83.3 m/s
Convert pilot's weight into mass:
760 N = 77.55 kg
Fnet=ma
n-mg=m(v^2/R)
n=(77.55 kg)(((83.3 m/s)^2)/160 m)+(77.55 kg)(9.8 m/s^2)
n=3363.2 N+760 N=4123 N
Answer:
The volume at the surface is 10.97 L.
Explanation:
Given that,
Volume = 5.5 L
Height = 10 m
Density of sea water= 1025 kg/m³
We need to calculate the pressure at that point
Using formula of pressure

Put the value into the formula


We need to calculate the volume at the surface
Using equation of ideal gas

So, for both condition

Put the value into the formula


Hence, The volume at the surface is 10.97 L.
Answer: 3 A
Explanation:
According to<u> Ohm's law</u>:
Where:
is the voltage
is the resistance of the resistor
is the electric current (the value we want to find)
Isolating
:


Finally:

Answer:
External force on him will be 112 N
Explanation:
We have given the mass of the sprinter m =70 kg
Acceleration of the sprinter 
We have to find the net external force
According to second law of motion force = mass ×acceleration
Force is dependent on the mass and acceleration
So 
So external force will be 112 N