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Diano4ka-milaya [45]
3 years ago
9

What is 2000(2000^2000)?

Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

Answer:

A. 2000²⁰⁰¹

Step-by-step explanation:

2000(2000²⁰⁰⁰) = 2000²⁰⁰⁰+1 = 2000²⁰⁰¹

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Organize the given volumes of cubes as either a perfect cube or not-perfect cube.
stiks02 [169]

Answer:

343m3,8m3,1000m3 for Perfect squares

300m3,9m3,900m3 for Not-perfect squares

Step-by-step explanation:

Did an assignment on edge

4 0
3 years ago
The surface area of a triangular pyramid is 1836 ft2.
Archy [21]
A triangular pyramid has 4 triangular faces. If all 4 have the same area, then one of them has area 1/4 of the surface area, 1836. That gives 459 sq ft as the area of one of the triangular faces.
3 0
4 years ago
How many pints will you get from 112 cups
xxTIMURxx [149]

Answer:

56 pints

Step-by-step explanation:

There are 56 pints in 112 cups

4 0
3 years ago
0-6
dybincka [34]
<h3>Given :-</h3>
  • Pranav ran 20.3 km more than Branda

  • Pravin ran 38.6 km

\\  \\

To find :

  • No. of kilometers did Brenda run.

\\  \\

<h3>Let :</h3>

  • No. of kilometers ran by Brenda be x.

\\  \\

<h3>Solution:</h3>

\\  \\

Equation formed:-

\\  \\

Total distance covered by Pravan = More distance covered by Pravan + distance covered by Brenda.

Therefore:-

\\  \\

\leadsto \sf38.6 = 20.3 + x

Write the equation

\\  \\

\leadsto \sf38.6 - 20.3 =x

When we transfer 20.3 to left side the positive sign (+) will change into negative sign (–)

\\  \\

\leadsto \sf x = 38.6 - 20.3

Arrange the equation because x is always represented at left side.

\\  \\

\leadsto \boxed {\pmb{\sf x = 18.3}}\star

After subtracting 38.6 with 20.3 we will get result as 18.3 .

\\  \\

\therefore \red{ \underline{  \pmb{\frak{Distance  ~ covered ~by ~Brenda~ is ~equal ~to~18.3~kilometers}}}}

7 0
3 years ago
A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.
stich3 [128]

Answer:

The distance between 12m-sides is 5\sqrt{2}m.

Step-by-step explanation:

It is given that the parallelogram has sides 10m and 12m and an angle of 45°.

Draw an altitude from one 12m side to another 12 m side as shown in below figure.

The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.

Since angle C is acute angle therefore it must be 45 degree.

\sin\theta=\frac{perpendicular}{hypotenuse}

\sin C=\frac{BE}{BC}

\sin(45^{\circ})=\frac{d}{10}

\frac{1}{\sqrt{2}}=\frac{d}{10}

\frac{10}{\sqrt{2}}=d

\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=d

\frac{10\sqrt{2}}{2}=d

5\sqrt{2}=d

Therefore the distance between 12m-sides is 5\sqrt{2}m.

4 0
3 years ago
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