First, we need to get the concentration of [NaH2PO4]:
[NaH2PO4] =( mass / molar mass ) * volume L
when we have mass NaH2PO4 = 6.6 g & molar mass = 120g/mol & V = 0.355 L
So by substitution:
[NaH2PO4] = (6.6g / 120g/mol) * 0.355 L = 0.0195 M
then, we need to get the concentration of [Na2HPO4]:
[Na2HPO4]= (mass / molar mass ) * volume L
So by substitution:
[Na2HPO4] = (8g/ 142g/mol) * 0.355 L = 0.02 M
and when Pka of the 2nd ionization of phosphoric acid = 7.21
So by substitution in the following formula, we can get the PH:
PH = Pka + ㏒[A]/[AH]
∴PH = 7.21 + ㏒[0.02]/[0.0195]
∴ PH = 7.2
Answer: water (H2O): Water is an excellent example of hydrogen bonding. ...
chloroform (CHCl3): Hydrogen bonding occurs between hydrogen of one molecule and carbon of another molecule.
ammonia (NH3): Hydrogen bonds form between hydrogen of one molecule and nitrogen of another.
Explanation:
<span>When cooking frozen cheese ravioli, you should use three quarts of water instead of one so that the raviolis have room to move around in the boiling water and so that while they are moving around, they will not stick to each other or the pan.</span>
