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Zigmanuir [339]
3 years ago
14

C=h/[M(T2-T1)] solve for T1

Chemistry
1 answer:
vodka [1.7K]3 years ago
7 0

Explanation:

This is expressing as a subject of a formula of a specie.

This equation is used in solving for specific heat capacity of a material;

     equation:

         c = \frac{h}{M(T2 - T1)}

First cross multiply:

  c[M(T2 - T1)]  = h

Then multiply both sides by \frac{1}{c } :

\frac{1}{c }  x    c[M(T2 - T1)]   = \frac{1}{c }  x h

        M(T2 - T1) = \frac{h}{c}

Multiply both sides by \frac{1}{M}

\frac{1}{M}   x   M(T2 - T1)  = \frac{1}{M} x  \frac{h}{c}

    T2 - T1 = \frac{h}{Mc}

Now rearrange to produce;

    T1 = T2 + \frac{h}{Mc}

learn more:

Specific heat brainly.com/question/7210400

#learnwithBrainly

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Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.
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The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

<h3>Balanced equation </h3>

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

  • The mole ratio of the acid, H₃PO₄ (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 3

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of acid, H₃PO₄ (Ma) = 0.390 M
  • Volume of acid, H₃PO₄ (Va) = 24.5 mL
  • Molarity of base, Ca(OH)₂ (Mb) = 0.279 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

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brainly.com/question/14356286

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