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meriva
2 years ago
7

Which statement below BEST describes the difference between mixtures and pure substances? Group of answer choices Mixtures are m

ade of a single kind of matter but a pure substance is two or more substances that are chemically bonded. Pure substances can be physically separated but mixtures cannot be physically separated. Pure substances are not created through a chemical reaction and mixtures are the result of a chemical reaction. Mixtures can be physically separated but pure substances cannot be physically separated.
Chemistry
1 answer:
lianna [129]2 years ago
6 0

Answer:  <u>Mixtures can be physically separated but pure substances cannot be physically separated.</u>

Explanation: Mixtures can be physically separated by using methods that use differences in physical properties to separate the components of the mixture, such as evaporation, distillation, filtration and chromatography. A pure substance, any compound or element, can't be separated into different atoms by physical methods. Pure substances are compounds and elements (made up of the same atom or same molecule respectively), while mixtures are an assortment of different substances put together. Hope this helps ^-^.

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Answer:

Option A = 2.2 L

Explanation:

Given data:

volume of one mole of gas = 22.4 L

Volume of 0.1 mole of gas at same condition = ?

Solution:

It is known that one mole of gas at STP occupy 22.4 L volume. The standard temperature is 273.15 K and standard pressure is 1 atm.

For 0.1 mole of methane.

0.1/1 × 22.4 = 2.24 L

0.1 mole of methane occupy 2.24 L volume.

8 0
3 years ago
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An industrial chemist is studying a sample of an unknown metal. Describe two ways he could change the metal physically and two w
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Answer:

Some of the physical changes used by the industrial chemist in order to identify it is by scratching it with other metals in order to find the hardness of it. Trying to deform it in order to find the malleability, and to heat it and measure the temperature in order to find the melting point.  

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3 years ago
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3 years ago
A 0.105 L sample of an unknown HNO 3 solution required 35.7 mL of 0.250 M Ba ( OH ) 2 for complete neutralization. What is the c
oksano4ka [1.4K]

Answer: 0.17M

Explanation:

The equation for the reaction is :

2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O

From the balanced equation, we obtain :

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From the question, we obtain:

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MaVa / Mb Vb = nA / nB

(Ma x 0.105) / (0.25x0.0357) = 2

Cross multiply to express in linear form. We have:

Ma x 0.105 = 0.25 x 0.0357 x 2

Divide both side by 0.105. We have

Ma = (0.25 x 0.0357 x 2) / 0.105

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