1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sukhopar [10]
3 years ago
13

Calculate the heat needed to increase the temperature of 100. g water from 45.7 C to 103.5 C.

Chemistry
2 answers:
algol133 years ago
7 0

Answer:

249362.4 J

Explanation:

The following were Data were obtained from the question:

Mass (M) = 100g

Initial temperature (T1) = 45.7°C

Final temperature (T2) = 103.5°C

Heat of vaporisation (ΔHv) = 2260 J/g

Specific heat capacity (C) of steam = 1.90 J/g

Specific heat capacity (C) of water = 4.18 J/g

To calculate the heat needed to increase the temperature of water from 45.7°C to 103.5°C, the following must be observed:

Step 1:

Determination of the heat needed to raise the temperature of water from

45.7°C to its boiling point 100°C.

This is illustrated below:

Mass (M) = 100g

Initial temperature (T1) = 45.7°C

Final temperature (T2) = 100°C

Specific heat capacity (C) of water = 4.18 J/g

Change in temperature (ΔT) = T2 – T1 = 100°C – 45.7°C = 54.3°C

Heat (Q1) =?

Q = MCΔT

Q1 = 100 x 4.18 x 54.3

Q1 = 22697.4 J

Step 2:

Determination of the heat needed to vaporise 100g of water.

This is illustrated below:

Mass (M) = 100g

Heat of vaporisation (ΔHv) = 2260 J/g

Heat (Q2) =?

Q2 = MΔHv

Q2 = 100 x 2260

Q2 = 226000 J

Step 3:

Determination of the heat needed to raise the temperature of steam from 100°C to 103.5°C.

This is illustrated below:

Mass (M) = 100g

Initial temperature (T1) = 100°C

Final temperature (T2) = 103.5°C

Specific heat capacity (C) of steam = 1.90 J/g

Change in temperature (ΔT) = T2 – T1 = 103.5°C – 100°C = 3.5°C

Heat (Q3) =?

Q3 = MCΔT

Q3 = 100 x 1.9 x 3.5

Q3 = 665 J

Step 4:

Determination of the overall heat needed.

This is simply obtained by adding all the heat calculated above. This is illustrated:

QT = Q1 + Q2 + Q3

Q1 = 22697.4 J

Q2 = 226000 J

Q3 = 665 J

Total heat (QT) =..?

QT = Q1 + Q2 + Q3

QT = 22697.4 + 226000 + 665

QT = 249362.4 J

Therefore, the heat needed to increase the temperature of 100g of water from 45.7°C to 103.5°C is 249362.4 J

MA_775_DIABLO [31]3 years ago
4 0

Answer:

Total heat required to raise the temperature of water from 45.7°C to 103.5°C

= 249,362.4 J

Explanation:

The Heat required to raise the temperature of 100.0 g of water from 45.7°C to 103.5°C will be a sum of;

- The heat required to raise the 100 g of water from 45.7°C to water's boiling point of 100°C

- The Heat required to vaporize the 100 g of water at its boiling point

- The Heat required to raise the temperature of this vapour from 100°C to 103.5°C

1) The heat required to raise the 100 g of water from 45.7°C to water's boiling point of 100°C

Q = mCΔT

m = 100 g

C = 4.18 J/g.°C

ΔT = change in temperature = (100 - 45.7) = 54.3°C

Q = 100 × 4.18 × 54.3 = 22,697.4 J

2) The Heat required to vaporize the 100 g of water at its boiling point

Q = mL

m = 100 g

L = ΔHvaporization = 2260 J/g

Q = mL = 100 × 2260 = 226,000 J

3) The Heat required to raise the temperature of this vapour from 100°C to 103.5°C

Q = mCΔT

m = 100 g

C = 1.90 J/g.°C

ΔT = change in temperature = (103.5 - 100) = 3.5°C

Q = 100 × 1.9 × 3.5 = 665 J

Total heat required to raise the temperature of water from 45.7°C to 103.5°C

= 22,697.4 + 226,000 + 665

= 249,362.4 J

Hope this Helps!!!

You might be interested in
The soldiers are issued (infrared) goggles to help them see in the dark.
gregori [183]
"outside visible spectrum" would be the right way to define the power of the goggles provided to the soldiers to see at night. The correct option among all the options that are given in the question is the first option or option "A". I hope the answer comes to your great help.
6 0
3 years ago
Read 2 more answers
The MOST important biotic factor in this swamp would be the
Mamont248 [21]
Plants :)

Hope this helps!
6 0
3 years ago
Cryolite, Na3AlF6(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide. Balance the equation f
dmitriy555 [2]

<u>Answer:</u> The mass of cryolite produced is 51.48 kg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For aluminium oxide:</u>

Given mass of aluminium oxide = 12.5 kg = 12500 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of aluminium oxide = 101.96 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium oxide}=\frac{12500g}{101.96g/mol}=122.6mol

  • <u>For NaOH:</u>

Given mass of NaOH = 55.4 kg = 55400 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

\text{Moles of NaOH}=\frac{55400g}{40g/mol}=1389mol

  • <u>For HF:</u>

Given mass of HF = 55.4 kg = 55400 g

Molar mass of HF = 20 g/mol

Putting values in equation 1, we get:

\text{Moles of HF}=\frac{55400g}{20g/mol}=2770mol

For the given chemical reaction:

Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O(g)

By Stoichiometry of the reaction:

1 mole of aluminium oxide reacts with 6 moles of sodium hydroxide and 12 moles of HF.

So, 122.6 moles of aluminium oxide will react with (6\times 122.6)=735.6mol of sodium hydroxide and (12\times 122.6)=1471.2mol of HF

As, given amount of NaOH and HF is more than the required amount. So, they are considered as an excess reagent.

Thus, aluminium oxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aluminium oxide produces 2 moles of cryolite

So, 122.6 moles of aluminium oxide will produce = \frac{2}{1}\times 122.6=245.2mol of cryolite

Now, calculating the mass of cryolite by using equation 1:

Molar mass of cryolite = 209.94 g/mol

Moles of cryolite = 245.2 mol

Putting values in equation 1, we get:

245.2mol=\frac{\text{Mass of cryolite}}{209.94g/mol}\\\\\text{Mass of cryolite}=(245.2mol\times 209.94g/mol)=51477.3g

Converting this into kilograms, we use the conversion factor:

1 kg = 1000 g

So, 51477.3 g\times (\frac{1kg}{1000g})=51.48kg

Hence, the mass of cryolite produced is 51.48 kg

7 0
3 years ago
How many liters are in 3.45 moles of oxygen gas at STP?
just olya [345]

Answer:

22.4L of one mole of any gas

or you can use PV=nRT

3.45*22.4=77.28

Explanation:

5 0
2 years ago
Pa help po thanks! I need the answer ASAP
Korolek [52]

The object and description that matches is Object 2 and T.

Object 1 has no matching description.

<h3>Fish Aquarium Filter </h3>

A Fish aquarium filter is a filter whose function is to clean the water of debris, removes the toxic buildup of ammonia and nitrates, and aerates the water so that fish can in a conducive environment and breathe properly

<h3>Engine Oil Filter</h3>

An engine oil filter is a filter whose function is to filter and remove contaminants that may be present in the engine oil, transmission oil, lubricating oil, or hydraulic oil in order for proper functioning of the engine.

Therefore, the object and description that matches is Object 2 and T.

Object 1 has no matching description.

Learn more about filters and their uses at: brainly.com/question/10719424

6 0
2 years ago
Read 2 more answers
Other questions:
  • What metallic element is sometimes used in flares because it burns bright?
    5·2 answers
  • water is added to 200. ml of a 2.0 m solution of cacl2 to increase the volume of the solution to 450.ml. what is the new concent
    10·1 answer
  • Whose personal story did you read (if you read several, pick your favorite)? What was the most interesting or eye-opening part o
    7·1 answer
  • What happens if an atom loses a neutron?Its mass is lowered, but it is still the same element. Its mass stays the same, and it i
    6·2 answers
  • The structures of TeF4 and TeCl4 in the gas phase have been studied by electron diffraction.
    13·1 answer
  • Convert 236 mg MgP207 to moles. Use three significant figures in your answer.​
    6·1 answer
  • Biacetyl, the flavoring that makes margarine taste "just like butter," is extremely stable at room temperature, but at 200°C it
    9·1 answer
  • As: [Ar]4s23d104p3 [Ar]4s23d104p2 [Kr]4s24d104p3 [Kr]4s23d104p3
    10·2 answers
  • Which of these substances will conduct electricity? CuSO4(s) CuSO4(aq) C5H12(l) CO2(g)
    8·1 answer
  • PLEASE HELP: You have been given 0.507 moles of cesium fluoride (CsF), determine the mass in grams of cesium fluoride that you h
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!