Question

A constant force is applied to an object, causing the object to accelerate at 9.0 m/s2 . What will the acceleration be if the force is doubled?

Answer 1

When the constant force applied to an object, causing an acceleration of 9.0 m/s², is doubled, the final acceleration is also doubled.  

The acceleration is related to the force by Newton's second law:

$F = ma$

Where:

F. is the force applied

m: is the object's mass

a: is the acceleration

For the first case, when a constant force is applied and the acceleration is 9.0 m/s², we have:

$F_{1} = ma_{1} = 9m$   (1)

Now, when the force is doubled:

$F_{2} = ma_{2}$

$2F_{1} = ma_{2}$  

$a_{2} = \frac{2F_{1}}{m} = \frac{2*9m}{m} = 18 m/s^{2}$

Therefore, when the force doubles, the acceleration also doubles.

To find more about Newton's second law, go here: brainly.com/question/23845187?referrer=searchResults  

I hope it helps you!