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3 years ago

How many significant figures does the number 91010.0 have?

Physics

2 answers:

pantera1 [17]3 years ago

8 0

It has 6 significan figures I think because if you count al the numbers it gives a total of 6 numbers

kirza4 [7]3 years ago

5 0

Answer:

6 (six)

Explanation:

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An automobile of mass 1500kg moving at 25.0m/s collides with a truck of the mass 4500kg at rest. The car and the truck bounce of

Mekhanik [1.2K]

Answer: Both forces are equal each other.

Explanation:

If we assume that no external forces act during the collision (based on the fact that the collision time is very small), total momentum must be conserved, and Newton's 3rd law must apply.

If the total momentum is conserved, the change in momentum for the automobile (caused by the truck) must be equal to the one caused to the truck by the car.

This change in momentum is caused by internal forces, which must be equal each other (even though of opposite signs).

Another way to explain this, is that by Newton's 3rd Law, the force applied by the automobile to the car, must be equal and opposite to the one the truck is applying to the car at the same time.

6 0

3 years ago

When expressing the unit for work, which of the following is the correct choice?

hram777 [196]

I need to write 20 characters but your answer is Joule

4 0

3 years ago

A 0.600 kg block is attached to a spring with spring constant 15 N/m. While the block is sitting at rest, a student hits it with

gulaghasi [49]

Answer:

8.8 cm

31.422 cm/s

Explanation:

m = Mass of block = 0.6 kg

k = Spring constant = 15 N/m

x = Compression of spring

v = Velocity of block

A = Amplitude

As the energy of the system is conserved we have

$\dfrac{1}{2}mv^2=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{mv^2}{k}}\\\Rightarrow A=\sqrt{\dfrac{0.6\times 0.44^2}{15}}\\\Rightarrow A=0.088\ m\\\Rightarrow A=8.8\ cm$

Amplitude of the oscillations is 8.8 cm

At x = 0.7 A

Again, as the energy of the system is conserved we have

$\dfrac{1}{2}kA^2=\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2\\\Rightarrow v=\sqrt{\dfrac{k(A^2-x^2)}{m}}\\\Rightarrow v=\sqrt{\dfrac{15(0.088^2-(0.7\times 0.088)^2)}{0.6}}\\\Rightarrow v=0.31422\ m/s$

The block's speed is 31.422 cm/s

4 0

3 years ago

A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step

Crazy boy [7]

From laws of motion:

$S = ( \frac{v + u}{2} ) \times t$
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s

Substitute the values, hence:
$S = ( \frac{0 + 36}{2} ) \times 6$
$S = (18) \times 6 \\ \\ S = 108m$

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m

6 0

4 years ago

The mass of an object with 500 J of kinetic energy moving with a velocity of 5 m/s is

Ann [662]

40kg

Explanation:

Given parameters:

Kinetic energy = 500J

Velocity = 5m/s

Unknown:

Mass of the object = ?

Solution: