Answer:
Angular acceleration, is
Explanation:
Given that,
Initial speed of the drill,
After 4.28 s of constant angular acceleration it turns at a rate of 28940 rev/min, final angular speed,
We need to find the drill’s angular acceleration. It is given by the rate of change of angular velocity.
So, the drill's angular acceleration is .
Given
Car 1
m1 = 1300 kg
v1 = 20 m/s
m2 = 900 kg
v2 = -15 m/s
(Negative sign shows that direction of car 2 is opposite to car 1)
Procedure
As per the conservation of linear momentum, "The total momentum of the system before the collision must be equal to the total momentum after the collision". And this applies to the perfectly inelastic collision as well. Then the expression is,
Thus, we can conclude that the speed and direction of the cars after the impact is 5.68 m/s towards the first car.
Answer:
Vf = 21.5 [m/s]
Explanation:
To solve this problem we must use the following kinematics equation:
where:
Vf = final velocity [m/s]
Vi = initial velocity = 0
a = aceleration = 4.3 [m/s^2]
t = time = 5 [s]
Now replacing:
Vf = 0 + (4.3*5)
Vf = 21.5 [m/s]