Question

A cube with sides of area 48 cm^2 contains a 28.7 nanoCoulomb charge. Find the flux of the electric field through the surface of the cube in unis of Nm^2/C.
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Answer 1

Answer:

The flux of the electric field through the surface is 3.24\times10^{3}\ Nm^/C[/tex].

Explanation:

Given that,

Area of cube = 48 cm²

Charge = 28.7 nC

We need to calculate the flux of the electric field through the surface

Using formula Gauss's law

The electric flux through any closed surface,

$\phi =\dfrac{q}{\epsilon_{0}}$

Where, q = charge

Put the value into the formula

$\phi=\dfrac{28.7\times10^{-9}}{8.85\times10^{-12}}$

$\phi =3.24\times10^{3}\ Nm^/C$

Hence, The flux of the electric field through the surface is 3.24\times10^{3}\ Nm^/C[/tex].