If other tickmarks are labeled, then you could do some detective work (of sorts) to figure out the unlabeled tickmarks.
For example, let's say we had a number line with 1,2,3,... and let's say that 7 was covered up or erased or smudged. So we have 1,2,3,4,5,6,__,8,9. We could then easily determine that 7 must go in that blank spot. This is just one example of course.
Another example could be that if we had a tickmark right in the middle of two whole numbers, say 0 and 1. This unlabeled tickmark would most likely be 1/2 = 0.5 as its at the halfway point between 0 and 1.
Answer:
16pi mi
Step-by-step explanation:
The smallest circumference for a given area is that of a circle with that area. The area is given by ...
A = πr²
so we can find r as ...
64π = πr²
r = √64 = 8 . . . . miles
The circumference of this circle is ...
C = 2πr = 2π·(8 mi) = 16π mi
The circumference of the area is at least 16π miles.
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If the shape is not constrained to a circle, the circumference can be anything you like.
You would do 3 times 5 mines 5 which equals 10 and the you would do 5x12
The simplest form is 3/8. this because 4 divides both sides
So an even number is represented as 2n where n= a whole number
an odd is 1 more than an even so 2n+1 is odd
so even+odd=2n+2n+1=4n+1=
we see 2 2n's in there which are even
(even)+(even)+1
we know that even+even=even try that withe any 2 even numbers
then +1 means it's odd so therefor it is always true
