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NeTakaya
3 years ago
7

Use a net to find the surface area of the prism 32cm by 12cm by 6.5

Mathematics
1 answer:
Masteriza [31]3 years ago
5 0

Answer:

76.16

Step-by-step explanation:

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A farmer has 15 boxes of eggs and there are 6 eggs in each box. Therefore it will be part to whole. The bigger number is always the whole. 6:15 is the ratio.
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The function p(x) = –2(x – 9)2 + 100 is used to determine the profit on T-shirts sold for x dollars. What would the profit from
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Which number line shows point A at 3, point B at −1.5, point C at , and point D, which is the opposite of point A?
Oduvanchick [21]

Step-by-step explanation:

We have that point A is at 3.

This is 3 units to the right of 0 on the number line.

The point that is opposite of A should be 3 units to the left of 0.

That point will be at -3.

Therefore you have to choose the point that is on -3.

It should be similar to one in the attachment.

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3 years ago
Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
lana66690 [7]

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

which is a circle centered at (0, -10, 3) of radius \sqrt{21}.

3 0
3 years ago
A pitcher holds 3/4 gallons of kool-aid. Martin wants to pour equal amounts of kool- aid into 6 smaller cotainers. How much kool
statuscvo [17]

Answer:

\dfrac{1}{8}\ gallons

Step-by-step explanation:

Amount of kool - aid that the pitcher can hold = \frac{3}4 gallons

There are 6 smaller containers in which this kool - aid is to be adjusted.

Also, the volume of the smaller containers is equal to each other i.e. the containers are identical to each other in terms of volume.

To find:

The amount of kool - aid that each container can hold?

Solution:

Volume of all the smaller containers combined = Volume of the kool - aid available

Let the volume of one smaller container = V

V + V + V + V + V + V = \dfrac{3}{4}\ gallons

\Rightarrow 6V = \dfrac{3}{4}\ gallons\\\Rightarrow V = \dfrac{3}{4\times 6 }\ gallons\\\Rightarrow V=\bold{\dfrac{1}{8}\ gallons}

\frac{1}{8}\ gallons of kool - aid is the amount that each smaller can hold.

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