Answer:
Explanation:
<u>1) Calculate the volume of the water in the tank.</u>
- Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
- Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
- Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.
<u>2) Calculate the weight of 21 ft³ of water.</u>
Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:
- 62.4 lb / 1 ft³ = x / 21 ft³
Solve for x:
- x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.
So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.
Answer:
I think I explained the circle one before so I'll explain the left question because I wanted some points.
here,
area of circle is πr² which is given= 12 π cm²
so πr²= 12π
r= 2√3
d= 2r= 4√3
AB is diameter so AB= 4√3
0.000000084
we need to move the decimal 8 places to the right
8.4* 10^-8
8 shakers will fit becuase 4 shakers equal 5 ounces and you multiply it by two and you get 10