Answer is: 12,6% (1/8) <span>percentage of the sample will remain.
</span>c₀ - initial amount of C-14.<span>
c - amount of C-14 remaining
at time.
t = 5700</span> y.<span>
First calculate the radioactive decay rate constant λ:
λ = 0,693 ÷ t = 0,693 ÷ 5700</span> y = 0,000121 1/y = 1,21·10⁻⁴ y.
c = c₀·e∧-λ·t.
c = 2000 · e∧-(0,000121 1/y · 17100 y).
c = 252 g.
ω = 252 g ÷ 2000 g = 0,126 = 12,6%.
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The ionization energy decreases from top to bottom in groups, and increases from left to right across a period. Thus, helium has the largest first ionization energy
From the diagram, structure 1 would be the chloroplast and it represents the site of photosynthesis.
<h3>Plant cells</h3>
The image (see attached) is that of a plant cell and structure labeled 1 is the chloroplast.
The chloroplast of plant cells acts as the site of photosynthesis where inorganic materials are used to synthesize carbohydrates.
Plants generally serve as producers in food chains and thus, chloroplast helps sustain life.
More on plant cells can be found here: brainly.com/question/1894299