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GREYUIT [131]
3 years ago
5

Free 5 points!!! (just trust me on this)

Chemistry
2 answers:
MArishka [77]3 years ago
8 0

Answer:

FREE

Explanation:

This is a good thing because... well... its free

kirza4 [7]3 years ago
8 0

ANSWER: I dont see a reson why not

: |

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In the laboratory, a general chemistry student measured the pH of a 0.529 M aqueous solution of phenol (a weak acid), C6H5OH to
Artyom0805 [142]

Answer:

The dissociation constant of phenol from given information is 9.34\times 10^{-11}.

Explanation:

The measured pH of the solution = 5.153

C_6H_5OH\rightarrow C_6H_5O^-+H^+

Initially      c

At eq'm   c-x       x  x

The expression of dissociation constant is given as:

K_a=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OOH]}

Concentration of phenoxide ions and hydrogen ions are equal to x.

pH=-\log[x]

5.153=-\log[x]

x=7.03\times 10^{-6} M

K_a=\frac{x\times x}{(c-x)}=\frac{x^2}{(c-x)}=\frac{(7.03\times 10^{-6} M)^2}{ 0.529 M-7.03\times 10^{-6} M}

K_a=9.34\times 10^{-11}

The dissociation constant of phenol from given information is 9.34\times 10^{-11}.

4 0
4 years ago
What mineral is the hardest known substance in nature?
shusha [124]
The mineral that is the hardest known substance in nature is a diamond. 
Hope this helps. 



3 0
4 years ago
Read 2 more answers
Calculate the mass of hydrogen in 500 g of Al(C2H3O2)3
Zigmanuir [339]
<span>Answer is: the mass of hydrogen is 22,05 grams.
m(</span>Al(C₂H₃O₂)₃)<span> = 500 g.
M</span>(Al(C₂H₃O₂)₃) = 27 + 6 ·12 + 9 · 1 + 6 · 16 · g/mol = 204 g/mol.<span>
n</span>(Al(C₂H₃O₂)₃) = m(Al(C₂H₃O₂)₃) ÷ M(Al(C₂H₃O₂)₃).
n(Al(C₂H₃O₂)₃) = 500 g ÷ 204 g/mol.
n(Al(C₂H₃O₂)₃) = 2,45 mol.
n(Al(C₂H₃O₂)₃) : n(H) = 1 : 9.
n(H) = 22,05 mol.
m(H) = 22,05 mol · 1 g/mol
m(H) = 22,05 g.

3 0
3 years ago
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When this element was discovered, it exhibited luster and malleability, and it reacted very vigorously with water. This element
rjkz [21]
The answer is potassium
5 0
3 years ago
How do I do this? It's in Chemistry, and it has to do with Single Replacement
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Is there any more to the picture?
4 0
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