<u>Answer:</u> The value of
for the chemical equation is 
<u>Explanation:</u>
For the given chemical equation:

To calculate the
for given value of Gibbs free energy, we use the relation:

where,
= Gibbs free energy = 78 kJ/mol = 78000 J/mol (Conversion factor: 1kJ = 1000J)
R = Gas constant = 
T = temperature = 1000 K
= equilibrium constant in terms of partial pressure = ?
Putting values in above equation, we get:

Hence, the value of
for the chemical equation is 
Number 18 is correct, number 19 is the particles speed up and the substance expands, and number 20 is decrease in volume
<span>Answer: option (3) energy, charge and mass.
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<span>Explanation:
</span><span />
<span>1) The conservation of energy is a universal principle: energy is neither created nor destroyed. This is the first law of thermodynamic.
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<span>2) Mass conservation is another universal principle: mass is neither created nor destroyed. This principle is the base of the stochiometry: thas mass of the reactans equal the mass of the products. Another consequence, since the atoms are not transformed in the chemical reactions, is that the number of each kind of atoms in the reactants equal the number of the same kind of atoms in the products.
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<span>3) The third principle is the conservation of charge. Also, charge is neither created nor destroyed. The electrons gained/lost by one species are lost/gained by other species. So, when one atom or molecule is oxidized other is reduced.</span>
Answer:
The highlighted words in the explanation.
Explanation:
A clue comes by considering the noble gas elements, the rightmost column of the periodic table. These elements—helium, neon, argon, krypton, xenon, and radon—do not form compounds very easily, which suggests that they are especially stable as lone atoms. What else do the noble gas elements have in common?
From the balance and the growth you are talking to me, we can say that <span>it would be an inequality of 2x > 4x +12 so in that case it would be in the motnh number 6 where you would find a greater balance.</span>