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Irina18 [472]
2 years ago
11

-5+22=r-4+3r+5 I need help please and thank u

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
6 0

Answer:

r = 4

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

-5 + 22 = r - 4 + 3r + 5

<u>Step 2: Solve for </u><em><u>r</u></em>

  1. Combine like terms:                    17 = 4r + 1
  2. Subtract 1 on both sides:             16 = 4r
  3. Divide 4 on both sides:               4 = r
  4. Rewrite:                                        r = 4

<u>Step 3: Check</u>

<em>Plug in r to verify it's a solution.</em>

  1. Substitute:                    -5 + 22 = 4 - 4 + 3(4) + 5
  2. Add/Subtract:               17 = 3(4) + 5
  3. Multiply:                        17 = 12 + 5
  4. Add:                              17 = 17
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A metalworker has a metal alloy that is 15​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
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18 kg of 15% copper and 72 kg of 60% copper should be combined by the metalworker to create 90 kg of 51% copper alloy.

<u>Step-by-step explanation:</u>

Let x = kg of 15% copper alloy

Let y = kg of 60% copper alloy

Since we need to create 90 kg of alloy we know:

x + y = 90

51% of 90 kg = 45.9 kg of copper

So we're interested in creating 45.9 kg of copper

We need some amount of 15% copper and some amount of 60% copper to create 45.9 kg of copper:

0.15x + 0.60y = 45.9

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substituting that value in for x

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Therefore, in order to create 90kg of 51% alloy, we'd need 18 kg of 15% copper and 72 kg of 60% copper.

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