All ball is thrown into the air with an upward velocity of 24 ft/s. Its height h in feet after t seconds is given by the functio
n h=-16t^2+24t+7. a. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball's maximum height?
For this case what you should do is use the following trigonometric relationship: sin (x) = C.O / h Where x: angle C.O: opposite leg h: hypotenuse Substituting the values we have: sen (60) = long / h sen (60) = 3 / h h = 3 / sin (60) h = 3.46 Answer: h = 3.46
