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3 years ago

14

What are the differences between proton, neutron, and electron

1 answer:

AysviL [449]3 years ago

6 0

A proton is positive energy, a neutron is neutral, and an electron is negative charge. Protons and neutrons are in the nucleus of an atom and electrons are on the electron cloud.

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Which picture or pictures show a molecule?

MrRissso [65]

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3 years ago

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Interpret the electron configuration

Svetach [21]

Answer:

Ca for calcium

20 electrons

2-2s electron

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3 years ago

Explain how might a renewable energy source become nonrenewable

Marysya12 [62]

If you use up renewable resources faster than you can reproduce them, then they're really non-renewable. For example, if you're cutting down trees faster than they're growing, then you'll eventually run out of trees, even though they're "renewable". Technically, oil is renewable, but it takes millions of years to create, so it's non-renewable.

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3 years ago

MEASUREMENT AND MATTER Interconverting temperatures in Celsius and Kelvins The metal osmium becomes superconducting at temperatu

nexus9112 [7]

Answer: $-272^0C$ .

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like $^0C$ and $K$

These units of temperature are inter convertible.

We are given:

Temperature of the gas = $655mK=0.655K$ (1mK=0.001 K)

Converting this unit of temperature into $^0C$ by using conversion factor:

$(t-273.15)^0C=tK$

$273.15K=0^0C$

Thus $0.655K=(0.655-273.15)^0C=-272^0C$

Thus the temperature is $-272^0C$ .

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3 years ago

NH₄NO₃ → N₂O + 2H₂O When 45.70 g of NH₄NO₃ decomposes, what mass of each product is formed?

Anna007 [38]

Answer: 25.13 g of $N_2O$ and 20.56 g of $H_2O$ will be produced from 45.70 g of $NH_4NO_3$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} NH_4NO_3=\frac{45.70g}{80.04g/mol}=0.571moles$

The balanced chemical equation is:

$NH_4NO_3\rightarrow N_2O+2H_2O$

According to stoichiometry :

1 mole of $NH_4NO_3$ produce = 1 mole of $N_2O$

Thus 0.571 moles of $NH_4NO_3$ will require= $\frac{1}{1}\times 0.571=0.571moles$ of $N_2O$

Mass of $N_2O=moles\times {\text {Molar mass}}=0.571moles\times 44.01g/mol=25.13g$

1 mole of $NH_4NO_3$ produce = 2 moles of $H_2O$

Thus 0.571 moles of $NH_4NO_3$ will require= $\frac{2}{1}\times 0.571=1.142moles$ of $H_2O$

Mass of $H_2O=moles\times {\text {Molar mass}}=1.142moles\times 18g/mol=20.56g$

Thus 25.13 g of $N_2O$ and 20.56 g of $H_2O$ will be produced from 45.70 g of $NH_4NO_3$

5 0

3 years ago