The answer to your question is a shot
Answer:
Explanation:
The following is written in Java. It creates the function num_eights and uses recursion to check how many times the digit 8 appears in the number passed as an argument. A test case has been created in the main method and the output can be seen in the image below highlighted in red.
public static int num_eights(int pos){
if (pos == 0)
return 0;
if (pos % 10 == 8)
return 1 + num_eights(pos / 10);
else
return num_eights(pos / 10);
}
Answer:
a) Generate a new public and private key
Explanation:
You encrypt a message using the recipient's public key and the recipient decrypts the message using his own private key. Only the public key can be known by an external agent. The private key is for the individual and is not expected to be shared. In the event that the recipient cannot decrypt the message, it is unsafe to send one's private key to him. He does not even need one's private key to decrypt the message, he needs his own private key.
The best thing to do is to generate another means of security by generating new public and private key so that the sender encrypts the message with the new public key and the receiver decrypts it using his new private key.
Option B is wrong because, if the encryption is removed, the aim, which is to secure the message from intruders is not achieved.
Option B is what i would say
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The answer is Status bar
Hope my answer Helps! :)
