Ionic compound is formed by negative and positive ions, these ions form ionic bond
Answer:
maybe 200g
I don't know thats just a guess
HOPE ITS TURE
Steps 1 and 3 are correct rate
Answer:
- 13.56 g of sodium chloride are theoretically yielded.
- Limiting reactant is copper (II) chloride and excess reactant is sodium nitrate.
- 0.50 g of sodium nitrate remain when the reaction stops.
- 92.9 % is the percent yield.
Explanation:
Hello!
In this case, according to the question, it is possible to set up the following chemical reaction:

Thus, we can first identify the limiting reactant by computing the yielded mass of sodium chloride, NaCl, by each reactant via stoichiometry:

Thus, we infer that copper (II) chloride is the limiting reactant as it yields the fewest grams of sodium chloride product. Moreover the formed grams of this product are 13.56 g. Then, we take 13.56 g of sodium chloride to compute the consumed mass sodium nitrate as it is in excess:

Therefore, the leftover of sodium nitrate is:

Finally, the percent yield is computed via:

Best regards!
Take a look at their electronegativity values for this one. Electronegativity is the relative attraction that a atom in a molecule has for the shared pair of electrons in a covalent bond<span>. Salt is Sodium Chloride which is NaCl. Na has an electronegativity value of 0.93. Cl has an electronegativity value of 3.16. The difference between the two is 2.23. This is much higher than 1.7 (a pure covalent bond e.g. Oxygen-Oxygen bond O2) therefore it is a highly ionic compound. If this was less than 1.7 it would be a polar covalent molecule. </span>