With the given formula, we can calculate the amount of CO₂ using the balance equation but we first need the moles of CH₄
1) to find the moles of CH₄, we need to use the ideal gas formula (PV= nRT). if we solve for n, we solve for the moles of CH₄, and then we can convert to CO₂. Remember that the units put in this formula depending on the R value units. I remember 0.0821 which means pressure (P) has to be in atm, volume (V) in liters, the amount (n) in moles, and temperature (T) in kelvin.
PV= nRT
P= 1.00 atm
V= 32.0 Liters
n= ?
R= 0.0821 atm L/mol K
T= 25 C= 298 K
let plug the values into the formula.
(1.00 x 32.0 L)= n x 0.0821 x 298K
n= (1.00 x 32.0 L )/ (0.0821 x 298)= 1.31 moles CH₄
2) now let's convert the mole of CH₄ to moles to CO₂ using the balance equation
1.31 mol CH₄ (1 mol CO₂/ 1 mol CH₄)= 1.31 mol CO₂
3) Now let's convert from moles to grams using the molar mass of CO₂ (find the mass of each atom in the periodic table and add them)
molar mass CO₂= 12.00 + (2 x 16.0)= 44.0 g/mol
1.31 mol CO₂ ( 44.0 g/ 1 mol)= 57.6 g CO₂
Note: let me know if you any question.
2Al (s) + 3Fe(NO3)2 (aq) → 3Fe (s) + 2Al(NO3)3 (aq)
Find the pure amount of iron nitrate solution:
325 g x 87.5% = 284.375 g
Convert 284.375g into mols by dividing by molar mass of the iron nitrate solution
Molar mass of iron nitrate = 55.85 g/mol + 2x14g/mol + 6x16g/mol = 179.85 g/mol
Moles of iron nitrate = 284.375 g / 179.85 g/mol = 1.58
Stoichiometry
3 mols of iron nitrate / 3 mols of iron = 1.58 mols of iron nitrate / x mols of iron
x = 1.58 mols of iron.
Convert that in grams by multiplying by the molar mass of iron
grams of iron = 1.58 mol x 55.85 g/mol = 88.24 g
Answer:b yes b yes c no c yes d yes d no
Explanation: wanna trade r o b l o x acc
I would probably say transformation of virus like molecules
