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Alex787 [66]
3 years ago
10

to produce 4.00 L of a 250 mM solution of sodium hydroxide, how many grams of naOH must be dissolved?

Chemistry
2 answers:
goldfiish [28.3K]3 years ago
4 0
Multiply the volume in liters (4.00L) by the concentration of the solution in molar (0.250M) to calculate the number of moles of soluto that you need, then multiply the number of moles by the molar mass of sodium hydroxide (39.99 g/mol) to calculate the mass.

4.00L x 0.250 M x 39.99g / 1L = 39.99g

Basically you need one mol of NaOH (39.99g) dissolved in 4 liters of solution.

Akimi4 [234]3 years ago
4 0

Answer: 1.56\times 10^{-3}g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

Molarity = 250mM = 250\times 10^{-3}M

n= moles of solute  

V_s = volume of solution in ml = 4L = 4000 ml

{\text {moles of solute}}=\frac{\text {given mass}}{\text {molar mass}}=\frac{xg}{40g/mol}=0.025x

Now put all the given values in the formula of molarity, we get

250\times 10^{-3}=\frac{0.025\times x\times 1000}{4000ml}

250\times 10^{-3}=\frac{0.025\times x\times 1000}{4000ml}

x=1.56\times 10^{-3}g

Therefore, the 1.56\times 10^{-3}g of NaOH must be dissolved.

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