A Hypothesis.
I Hope This Helps! (^_^)
Answer:
38.75 L
Explanation:
From the question,
Applying Boyles Law,
PV = P'V'....................... Equation 1
Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' = Final Volume of Argon gas.
make V the subject of the equation
V = P'V'/P.................... Equation 2
Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.
Substitute these values into equation 2
V = (456×2.94)/34.6
V = 38.75 L
How much momentum does 5000 kilogram have
Answer:
D) 7 before and 7 after
Step-by-step explanation:
Na₂O + 2HCl ⟶ 2NaCl + H₂O
3 atoms + 4 atoms ⟶ 2×2 atoms + 3 atoms
7 atoms ⟶ 4 atoms + 3 atoms
7 atoms ⟶ 7 atoms
There are seven atoms present before and after the reaction.
Answer:
474.92 mL.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT</em>.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n is constant, and have two different values of (P, V and T):
<em>P₁V₁T₂ = P₂V₂T₁</em>
<em></em>
P₁ = 740 mmHg, V₁ = 450 mL, T₁ = 16°C + 273 = 286 K.
P₂ = 760 mmHg, V₂ = ??? mL, T₂ = 37°C + 273 K = 310 K.
<em>∴ V₂ = P₁V₁T₂/P₂T₁ </em>= (740 mmHg)(450 mL)(310 K)/(760 mmHg)(286 K) = <em>474.92 mL.</em>
