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Luda [366]
3 years ago
5

Answer the following questions ( image) with the given options.​​

Chemistry
2 answers:
kondor19780726 [428]3 years ago
8 0

Answer:

ans: B) domestic liquid and solid water

wlad13 [49]3 years ago
6 0

Answer:

B. domestic liquid and solid water

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Given the reaction: solid sodium reacts with chlorine gas to form solid sodium chloride How many moles of the product result fro
lyudmila [28]

Answer:

number of moles of NaCl produce = 12 mol

Explanation:

Firstly, we need to write the chemical equation of the reaction and balance it .

Na(s) + Cl2(g) → NaCl(s)

The balanced equation is as follows:

2Na(s) + Cl2(g) → 2NaCl(s)

1 mole(71 g) of chlorine produces 2 moles(117  g) of sodium chloride

6 mole of chlorine gas will produce ? mole of sodium chloride

cross multiply

number of moles of NaCl produce = 6 × 2

number of moles of NaCl produce = 12 moles

number of moles of NaCl produce = 12 mol

3 0
3 years ago
Which historical era was marked the beginnings of European explorations, conquests of the Americas, trans-Atlantic slave trade a
Tomtit [17]

Answer : Option C) Early modern era


Explanation : The historical era which was marked by the beginnings of European explorations, conquests of the Americas, trans-Atlantic slave trade and the rise of a globally intertwined economy was Early modern era. It was later followed by the medieval period.

8 0
3 years ago
8. What is the % Al in Aluminum chromate?
Wittaler [7]
13.4255 ‎ ‎ ‎ ‎ ‎ ‎
8 0
3 years ago
The solubility of CO2 gas in water increases with increasing temperature. is not dependent on temperature. decreases with decrea
nadya68 [22]
What is the question?
7 0
3 years ago
Какая масса хлора и какое количество вещества необходимо для реакции с 12г магния при получении хлорида магния?
Naddika [18.5K]
Mg + Cl₂ = MgCl₂M(Mg) = 24г/моль  m 1 моль Mg = 24 г.По условию задачи дано 12г. Mg  Количество вещества n(Mg) =12÷24=0,5 мольРассуждаем: по уравнению реакции  с 1 моль магния реагирует 1 моль хлора, следовательно с 0,5 моль будет реагировать 0,5 моль хлора.1 моль хлора при н.у. занимает объем 22,4л. , тогда 0,5 моль хлора займет:0,5х22,4л.= 11,2л. Ответ: Для взаимодействии 12 г.  магния потребуется 11,2 л. хлора.
7 0
3 years ago
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