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erik [133]
3 years ago
11

PLEASE ANSWER I REALLY NEED THIS

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

y=x+1

Step-by-step explanation:

(3,4)

(-1,0)

(0-4)/(-1-3)=1

1 is slope

y intercept 1

x intercept -1

y=x+1

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Step-by-step explanation:

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2 years ago
What is the 22nd term of the arithmetic sequence 12, 17, 22, 27, …?
melomori [17]
In simple words you just find what is being added to each term in order to get the next term. Subtracting 17 by 12 you get 5, 22 minus 17 is 5 as well. Now that what is being added is found, you go by the last term given which is 27. You keep adding 5 to the number until you get to the 22nd term which would result in 117. If you would want to know the equation in order for it to be plugged in then you would use f(x)= 7+5x . You would want to use this equation instead of f(x)= 12+5x because putting 1 as x would make it equal to 17 which is NOT the first term but the second.
4 0
3 years ago
Read 2 more answers
Please help me..will give all the good stuff
Anika [276]

1. 14 loaves are needed for 63 customers

2.  90 loaves

3. 4.5 loaf

Step by Step:

9/2= 4.5

4.5x4= 18

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I multiplied and divided everything by 4.5 so one loaf of bread is 4.5.

(Correct me if I'm wrong)

I hope this helped! :)

6 0
2 years ago
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

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3 years ago
MUST HELP!!!! (+50 POINTS +BRANILEST +5 STARS +THANKS ON PROFILE)
Flura [38]

Answer:

Personification is your answer.

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