Answer:
- The function f(x) = 9,000(0.95)^x represents the situation.
- After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
- The range values, in the context of the situation, are limited to whole number
Step-by-step explanation:
The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.
Using x=2, we find the population in 2 years is expected to be about ...
f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120
Using x=4, we find the population in 4 years is expected to be about ...
f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330
Since population is whole numbers of bees, the range of the function is limited to whole numbers.
The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.
The choices listed above are applicable to the situation described.
The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.
Answer:
69x420=28,980
Step-by-step explanation:
i will
Answer:
$42.80
Step-by-step explanation:
We can set up an equation to solve this as such
Answer:
multiply both sides by 30 in fraction form 30 / 30
& 570 for the blank square for numerator of 30
Step-by-step explanation:
