Question

A car of mass 1200Kilograms moving at 50 m/s the driver applies the brakes for 0.08 seconds and the castles down to 10 meter per second calculate the The change of moment

Answer 1

Initial velocity=u=15m/s

Final velocity=v=10m/s

Time=0.08s

$\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}$

$\\ \sf\longmapsto Acceleration=\dfrac{10-15}{0.08}$

$\\ \sf\longmapsto Acceleration=\dfrac{-5}{0.08}$

$\\ \sf\longmapsto Acceleration=-62.5m/s^2$

Answer 2

Answer:

$accleration = \frac{v - u}{t} \\ = \frac{10 - 15}{0.08} \\ = \frac{ - 5}{0.08} = - 62.5m \: per \: sec {}^{2} .$