Answer:
Acceleration: ![9800 ft/s^2](https://tex.z-dn.net/?f=9800%20ft%2Fs%5E2)
Explanation:
The acceleration of an object is equal to the rate of change of velocity:
![a=\frac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7D%7Bt%7D)
where
u is the initial velocity
v is the final velocity
t is the time taken for the velocity to change from u to v
For the space probe in this problem, we have:
u = 100 ft/s (initial velocity)
v = 5000 ft/s (final velocity)
t = 0.5 s (time taken)
Therefore, the acceleration is
![a=\frac{5000-100}{0.5}=9800 ft/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B5000-100%7D%7B0.5%7D%3D9800%20ft%2Fs%5E2)
Answer:
F = 7.50 10⁻⁶ N
Explanation:
The force of attraction between two bodies is given by the law of universal gravitation
F =
where m₁ and m₂ are the masses of the hides, r the distance that separates them and G the constant of attraction that is worth 6.67 10⁻¹¹ N m²/kg²
let's calculate
F = 6.67 10⁻¹¹ 500 900/2²
F = 7.50 10⁻⁶ N
Multiply 200x10 then you will have your answer
Answer:
0.25p.a
Explanation:
force=15N area=60m²
so pressure =force/area =15N/60m²=0.25p.a
Answer:
7.402%
Explanation:
Given that the total electrical energy used by the bulb in every second is 66.2 J.
The useful energy converted to light energy is 4.9 J.
As efficiancy (in %) = (Useful energy)/(Total energy) x 100
So, the efficiency of the bulb = (4.9/66.2)x100=7.402%
Hence, the efficiency of the bulb is 7.402%.