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AfilCa [17]
3 years ago
10

What is the mechanical advantage of an inclined plane that has a length of 9 feet and a height of 3 feet?

Physics
2 answers:
Rainbow [258]3 years ago
5 0

Answer:

it would be 3

Explanation:

because you have to divide the length by the height of the incline.

nignag [31]3 years ago
5 0

Answer:

3

Explanation:

Just finished the quiz on Edg 2021

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Mass m, moving at speed 2v, approaches mass 4m, moving at speed v. The two collide elastically head-on. Part A Find the subseque
meriva
Thank you for posting your question here at brainly. A mass of m moves with 2V towards in the opposite direction of a mass, 4m moving at a speed of V, the speed of m was 2/5V and the mass of 4m was 7.5V. I hope it helps.
4 0
3 years ago
Read 2 more answers
Two friends, Al and Jo, have a combined mass of 168 kg. At an ice skating rink they stand close together on skates, at rest and
Keith_Richards [23]

Answer: 91.94 kg

Explanation: Supoose Al's mass is m. The combined mass is 168kg, so Jo's mass is 168 - m.

The Law of Conservation of Momentum states that when two objects collide, the total momentum of both objects before the collision is the same as the total momentum of both objects after the collision.

At the beginning, Al and Jo are united without movement, so their initial momentum is zero.

After the release of their hands, Al goes in one direction and Jo moves to the opposite direction. Suppose the direction Al is moving is positive. Conservation of momentum will be

m_{1}v_{1}_{(f)}+m_{2}v_{2}_{(f)}=m_{1}v_{1}_{(i)}+m_{2}v_{2}_{(i)}

where

index i referes to initial momentum

index f to final momentum

index 1 refers to Al

index 2 to Jo

Calculating:

m(0.91)-[(168-m)(1.1)]=0

0.91m+1.1m-184.8=0

2.01m=184.8

m = 91.94

Al has a mass of 91.94 kg.

6 0
2 years ago
The electric force on object A by object B is F. If the charge of object B were only half as large as it is, but everything else
nalin [4]

Answer:

The new electric force on object B by object A is one half of the magnitude of the original force F, in the opposite direction. Equals -F/2

Explanation:

We are asked to demonstrate what happens when you reduce the magnitude of the charge of an object in an interactive system.

Assumptions.

The new force is F'

The system is isolated from other external interferences

The distance between objects A and B remains unchanged

Analysis.

The force F on object A by object B is given by the formula

F=(k*q,a*q,b)/d^2

where k is the Coulomb's Law constant, and equals 9x10^9 N/m s

q,a and q,b equals the original charges of objects A and B

d is the distance between objects A and B

Now, we are to calculate the new force, let's call it F', and following the same reasoning.

F'=(k*q',a*q',b)/d'^2

Given that only q', b is different to the original, we have that

F'=(k*q,a*q',b)/d^2

Now, q',b=q,b/2 and replacing

F'=(k*q,a*q,b)/(2*d^2)

Now we find the relation between F' and F

F'/F=[(k*q,a*q,b)/(2*d^2)]/[(k*q,a*q,b)/d^2]

Reducing similar terms

F'/F=1/2

However, we should also consider that the forces F and F' are in oposite directions, so simplifying the vectorial notation,

F'/F=-1/2, meaning that F'=-F/2

7 0
3 years ago
Air becomes a conductor when the electric field strength exceeds 3.01 × 106 N/C. Determine the maximum amount of charge that can
Blizzard [7]

Answer:

8.37×10⁻³ C.

Explanation:

The formula of electric field is given as

E = kq/r².......................... Equation 1

Where E = electric field, q = amount of charge, k = coulomb constant, r = radius of the sphere

make q the subject of the equation

q = Er²/k .................... Equation 2

Given: E = 3.01×10⁶ N/C, r = 5.0 m, k = 8.99×10⁹ Nm²/C².

Substitute into equation 2

q = (3.01×10⁶)(5²)/(8.99×10⁹)

q = (75.25/8.99)×10⁻³

q = 8.37×10⁻³ C.

Hence the maximum amount of charge = 8.37×10⁻³ C.

3 0
3 years ago
Solid to liquid examples<br> Gas to liquid examples
KATRIN_1 [288]
ANSWER:

SOLID TO LIQUID EXAMPLES:

• Ice melting into water

• Solid butter melting into liquid

• Heating rocks up so much they become magma or lava

• Gallium melting in your hand

GAS TO LIQUID EXAMPLES:

• Dew

• Water droplets on the glass of cold drink

• Rain

• Fogging of glass of spectacles when enter from cold to warmer place

HOPE THIS HELPS, BRAINLIEST WILL BE APPRECIATED, THANK YOU! :)
5 0
2 years ago
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