3 years ago

How does the density of fluid affect the magnitude of buoyancy acting on an object immersed in it

Physics

1 answer:

Oksi-84 [34.3K]3 years ago

5 0

Answer:

Explanation:

more the density , more will be the buoyant force acting on it , less the density less will be the buoyant force acting on it. This is why people float in dead sea and sink in other seas

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Answer:

carbon dioxide

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4 years ago

A time-varying horizontal force F(t) = At4 + Bt2 acts for 0.500 s on a 12.25-kg object, starting attime t = 1.00 s. In the SI sy

PSYCHO15rus [73]

Answer:

3.82 Ns

Explanation:

Time varying horizontal Force is given as

F(t) = A t⁴ + B t²

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Impulse imparted is given as

$I = \int_{0}^{t}Fdt$

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$I = \int_{0}^{1}(4.50 t^{4} + 8.75 t^{2})dt$

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3 years ago

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4 years ago

Rafe is placing his car on a lift to change the oil and oil filter. He needs to drive up the lift 1.5 meters and the lift raises

jeyben [28]

Answer:

104 IMA

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3 years ago

You drop a rock down a well that is 5.4 m deep. How long does it take the rock to hit the bottom of the well?

Natali5045456 [20]

Equation of motion:

$y_{f}=y_{o}+v_{o}t+ \frac{1}{2} at^{2}$

Since initial velocity is zero, the second term goes away:

$y_{f}=y_{o}+0+ \frac{1}{2} at^{2}$

$y_{f}=y_{o}+\frac{1}{2} at^{2}$

$y_{f}-y_{o}= \frac{1}{2} at^{2}$

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$5.4m= \frac{1}{2} at^{2}$

$\frac{2(5.4m) }{a} = t^{2}$

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$\frac{2(5.4m) }{9.81 \frac{m}{ s^{2} } } = t^{2}$

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3 years ago

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