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GREYUIT [131]
3 years ago
11

Two identical 0.25 kg balls are involved in a head-on collision. Ball A is initially travelling at 3.5 m/s, and ball B is inital

ly at rest. Determine the velocity of each ball after the collision.
Physics
1 answer:
Naddik [55]3 years ago
7 0

Answer:

a) mv(final):<0,0,0> minus mv(initial):<25,0,0> = <-25,0,0>

b) mv(final):<25,0,0> minus mv(initial):<0,0,0> = <25,0,0>

c) conservation of momentum makes it <0,0,0>

for a-b-c, momentum_system + momentum_surroundings = 0

Explanation:

Hope this helps

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6 0
3 years ago
Problem: A lossless 50-Ω transmission line is terminated in a load with ZL = (50 + j25) Ω. Use the Smith chart to find the follo
Nadya [2.5K]

Answer:  (a). ΓL = 0.246 < 75°

(b). S =  1.7

(c). Zin =  (30-j)λ

(d). jreal = Arc Po = 0.105λ

(e). jmax = jreal = 0.105λ

Explanation:

attached is a document to help in understanding.

So we will begin with a step by step analysis of the problem.

from the diagram we have that  ZL = (50 + j25) Ω.

where ZL = ZL / Z₀ = 50 + j25 / 50 = 1 + j0.5

so we mark this on the chart as point 'P'

(a) ΓL = mP/m 'P' < Θ L = 1.7/6.9 < 75°

        ΓL = 0.246 < 75°

(b) This s-circle 's' is given thus s = r = 1.7 on the RHS of the chart

       S =  1.7

(c) we are to calculate the input impedance;

ζin = Q = 0.6 - j0.02

therefore Zin = Z₀ζin = 50(0.6 - j0.02) = (30-j)λ

Zin = (30-j)λ

(d) here we are taking R as the diameter opposite of Q on the s=circle

   so R = γin = 1.7 + j0.02

         yin = yo (γin) = (1.7+j0.02) / 50 = (34 + j0.4)ms

          yin = (34 + j0.4)ms

(e) move from 'p' on s-circle to 'o'

where maximum impedance = Znxl = Zos

which gives jreal =  Arc Po = 0.105λ

(f) jmax = jreal = 0.105λ

cheers i hope this helps

3 0
3 years ago
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