The correct option is this: SPONTANEOUS AT HIGH AND LOW TEMPERATURES.
There are two basic factors which determine whether a reaction will be spontaneous or not, these are the entropy and the enthalpy change. Different reactions have different entropy and enthalpy values. For a reaction that has an increased entropy and a decreased enthalpy, the chemical reaction will be spontaneous at all temperatures.
They push away from each other or repel due to the same charge they have.
286.8g of carbon dioxide forms when 95.6g of propane burns. The total atomic mass of the propane is 44(g). The total mass of the carbon dioxide formed when 44g of propane is burnt is 132(g). 44 divided by 44 equals 1. 132 divided by 44 equals 3. Therefore the amount of propane to carbon dioxide is in a 1:3 ratio. Therefore, 95.6 multiplied by 3 gives you the amount of carbon dioxide formed.
Answer:
Explanation:
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In this case, the undergoing reaction is:
Thus, since the Kp is given, it equals the partial pressure of carbon dioxide since the equilibrium expression only consider the gaseous species, hence:
Therefore, by considering the given pressure and temperature, one computes the moles of carbon dioxide:
In such a way, carbon dioxide and calcium oxide have a 1-to-1 molar relationship, thereby, the mass of calcium oxide turns out:
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