Question

What is the expression for “two less than the quotient of a number cubed and sixteen, increased by eight”?

Answer 1

Hi!

Let's go through each part of this equation, and write it in number form. 

2 less
-2

than the quotient of a number
a number = x
x/ - 2

cubed
x²/ - 2

and 16
x²/16 - 2

increased by 8
x²/16 - 2 + 8

The answer is x²/16 - 2 + 8

Hope this helps! :)
-Peredhel

Answer 2

Answer: Our expression is $\dfrac{x^3}{16}-2+8$

Step-by-step explanation:

Since we have given that

Let the number be 'x'.

Cubed of number = x³

Quotient of number cubed and sixteen is given by

$\dfrac{x^3}{16}$

Two less than the quotient is given by

$\dfrac{x^3}{16}-2$

Quotient is increased by eight is given by

$\dfrac{x^3}{16}-2+8$

So, our expression is $\dfrac{x^3}{16}-2+8$