Answer:
Option 1, No. The highest frequency of heterozygotes under Hardy-Weinberg equilibrium is 0.5
Explanation:
As per Hardy Weinberg’s equilibrium principle, the maximum frequency of heterozytotic individuals occur only when half of the population is dominant and recessive homozygous.
In other way when the sum of frequency of dominant and recessive species is equal to 0.5, only then the frequency of heterozygotes is maximum which in any case would not be higher than 0.5.
Hence, option 1 is correct
Answer:
Option D- frequency of the heterozygous qenotype
Explanation:
In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.
Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.
Answer:
Location A
Explanation:
Coastal areas have milder temperatures since they are close to water and water retains heat better than land (it's harder to warm it up and harder to cool it down). Due to this property of water, the location with the least temperature fluctuation would be the answer. Location A has the smallest range between the highest and lowest annual temperatures, making A the best answer choice. I hope I helped and that it's not too late for you.
The animal would have black fur, because the black fur is dominant over the white fur.
There is not any nucleus and nuclear bound organelles in prokaryotes....
