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Genrish500 [490]
3 years ago
14

Answer the below 20points If you dont know dont answer pls

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Substitute the f(x) and g(x) into f/g

\frac{\sqrt[3]{3x} }{5x+2}

To find the domain,

Get the denominator of the fraction so 5x + 2 and equal it to 0 and find x

5x + 2 = 0

5x = -2

x = \frac{-2}{5}

Therefore it's D

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Please read below. Thank you.
mel-nik [20]

Answer:

The equation of the circle is given by:

(x-a)^2+(y-b)^2=r^2

where:

(a,b) is the center  of the circle

given that the center of our circle is (2,3) with the radius of 5, the equation will be:

(x+2)^2+(y+3)^2=5^2

expanding the above we get:

x^2+4x+4+y^2+6y+9=25

this can be simplified to be:

x^2+4x+y^2+6y=25-13

x^2+y^2+4x+6y=12

6 0
3 years ago
Read 2 more answers
You are given 6 color cards: 1 red, 2 blue, 3 green. As you draw a card, YOU WILL KEEP IT. What is the probability of drawing a
nikitadnepr [17]

Answer:

3/6, 2/5, 0/5

Step-by-step explanation:

4 0
3 years ago
Complete the sentence 0.7 is 10 times as much as
rewona [7]
0.007 is the answer
3 0
3 years ago
consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

Generally the point of inflection is mathematically solved as

f''(x)=0

x^2+15x+6=0

Therefore inflection points is given as

x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

5 0
3 years ago
Find the area of the regular hexagon with perimeter 12 in. Write your answer in simplest radical form
Vinil7 [7]
I’m not sure if this helps, but the area of a hexagon with a perimeter of 12 inches would be 10.39 inches squared
7 0
3 years ago
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