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Genrish500 [490]
3 years ago
14

Answer the below 20points If you dont know dont answer pls

Mathematics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Substitute the f(x) and g(x) into f/g

\frac{\sqrt[3]{3x} }{5x+2}

To find the domain,

Get the denominator of the fraction so 5x + 2 and equal it to 0 and find x

5x + 2 = 0

5x = -2

x = \frac{-2}{5}

Therefore it's D

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Aleks [24]

Answer:

678.24 cubic centimeters

Step-by-step explanation:

7 0
3 years ago
This is the 4th question
gavmur [86]

Answer:

a) There are 9 outcomes.

b) **i have attached the tree diagram**

c) 1/9

d) 1/9

Step-by-step explanation:

Both events (choosing a shirt and choosing pants) are not mutually exclusive (disjoint). Meaning that both events can occur at the same time.

a) For a sequence of two events in which the first event can occur <em>m</em> ways and the second event can occur <em>n</em> ways, the events together can occur a total of <em>m</em> • <em>n</em> ways. So for this problem, you would do 3 • 3 which equals 9.

b) **tree diagram is attached**

c) Because there are two different events occurring (choosing a shirt and choosing pants) you need to multiply using the Multiplication Rule for Independent Events : P(A and B) = P(A) * P(B)

The probability of event A occurring (choosing a red shirt) is 1/3 and the probability of event B occurring (choosing brown pants) is also 1/3.

1/3 * 1/3 = 1/9

d) You would do the same thing here as part c.

The probability of event A occurring (choosing a blue shirt) is 1/3 and the probability of event B occurring (choosing blue pants) is again 1/3.

1/3 * 1/3 = 1/9

I hope this was helpful!! :)

4 0
3 years ago
in a box of chocolates, 1/5 of the chocolates contain nuts. the rest of the chocolates do not contain nuts. write down the ratio
valina [46]

Answer:

The ratio of the number of chocolates that contain nuts to the number of chocolates = 1:4

Step-by-step explanation:

The parameters given are;

Proportion of the box of chocolates that contain nuts = 1/5

Proportion of the box of chocolates that do not contain nuts = 1 - 1/5 = 4/5

Therefore, we have in a box of chocolates with five chocolates;

The number of chocolates that contain nuts = 1

The number of chocolates that do not contain nuts = 4

Which gives the ratio of the number of chocolates that contain nuts to the number of chocolates as 1:4.

4 0
3 years ago
Convert standard form 4x-2y=6
zysi [14]

Answer:

4x(-2)x(-2)=6

8 0
3 years ago
(3/5y^4)^-2 simplify this please
Usimov [2.4K]
(\frac{3}{5}y^4)^{-2}=(\frac{5}{3})^2y^{4\times-2}=\frac{25}{9y^8}
8 0
3 years ago
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