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PilotLPTM [1.2K]

2 years ago

9

already did the work, i just need someone to see if i did the tangent line right? the line has to touch the point 0.6! thank you

1 answer:

Dmitrij [34]2 years ago

5 0

The tangent looks good.

The curve is a bit crooked, at the 0.9 and 1.

But overall, cool graph.

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The element carbon has 3 naturally occurring isotopes. About 99% of carbon isotopes are C-12, about 1% are C-13, and a tiny amou

mezya [45]

Average atomic mass of carbon is 12.01 amu

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3 years ago

If a 20 g cannonball is shot from a 5 kg cannon with a velocity of 100

balu736 [363]

Strange as it may seem, the statement in the question appears to be <em>TRUE</em>.

-- Before the shot, neither the cannon nor the ball is moving, so their combined momentum is zero.

-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.

-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)

-- Momentum = (mass) x (velocity)

After the shot, the momentum of the cannonball is

(0.02 kg) x (100 m/s ==> that way)

Momentum of the ball = 2 kg-m/s ==> that way.

-- In order for both of them to add up to zero, the momentum of the cannon must be (2 kg-m/s this way <==) .

Momentum of cannon = (5 kg) x (V m/s this way <==)

2 kg-m/s this way <== = (5 kg) x (V m/s this way <==)

Divide each side by (5 kg):

V m/s = (2/5) m/s this way <==

Speed of recoil of the cannon = <em>-- 0.4 m/s</em>

3 0

3 years ago

2. Connect concepts on the left with a description on the right.

Nuetrik [128]

plzzz explain me your questions

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2 years ago

Find the Kinetic Energy of a<br>trailer of mass 30,000 kg moving at a<br>Speed of 60 km/h

olasank [31]

Explanation: Formulas you need to use:

K=0.5mass(Velocity^2)

km/h / 3.6 ===>M/S

Step 1:

convert km/h to m/s

Put the values in the formula :

3 0

3 years ago

Smaller mammals use proportionately more energy than larger mammals; that is, it takes more energy per gram to power a mouse tha

timama [110]

Answer:

10,200 Cal. per day

Explanation:

The mouse consumes 3.0 Cal each day, and has a mass of 20 grams. We can use this data to obtain a ratio of energy consumption per mass

$\frac{3.0 \ Cal}{20 g} = 0.15 \frac{Cal}{g}$ .

For the human, we need to convert the 68 kilograms to grams. We can do this with a conversion factor. We know that:

$1 \ kg = 1000 \ g$ ,

Now, we can divide by 1 kg on each side

$\frac{1 \ kg}{1 \ kg} = \frac{1000 \ g}{1 \ kg}$ ,

$1 = \frac{1000 \ g}{1 \ kg}$ .

Using this conversion factor, we can obtain the mass of the human in grams, instead of kilograms. First, lets take:

$mass_{human} = 68 \ kg$

We can multiply this mass for the conversion factor, we are allowed to do this, cause the conversion factor equals 1, and its adimensional

$mass_{human} = 68 \ kg * \frac{1000 \ g}{1 \ kg}$

$mass_{human} = 68,000 g$

Now that we know the mass of the human on grams, we can multiply for our ratio of energy consumption

$68,000 \ g * 0.15 \frac{Cal}{g} = 10,200 \ Cal$

So, we would need 10,200 Cal per day.

3 0

2 years ago