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PilotLPTM [1.2K]
2 years ago
9

already did the work, i just need someone to see if i did the tangent line right? the line has to touch the point 0.6! thank you

​

Physics
1 answer:
Dmitrij [34]2 years ago
5 0

The tangent looks good.

The curve is a bit crooked, at the 0.9 and 1.

But overall, cool graph.

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Two difference between thrust and upthrust .
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Read 2 more answers
An old millstone, used for grinding grain in a gristmill, is a solid cylindrical wheel that can rotate about its central axle wi
MAXImum [283]

Answer:

The answer is I=70,513kgm^2

Explanation:

Here we will use the rotational mechanics equation T=Ia, where T is the Torque, I is the Moment of Inertia and a is the angular acceleration.

When we speak about Torque it´s basically a Tangencial Force applied over a cylindrical or circular edge. It causes a rotation. In this case, we will have that T=Ft*r, where Ft is the Tangencial Forge and r is the radius

Now we will find the Moment of Inertia this way:

Ft*r=I*a -> (Ft*r)/(a) = I

Replacing we get that I is:

I=(200N*0,33m)/(0,936rad/s^2)

Then I=70,513kgm^2

In case you need to find extra information, keep in mind the Moment of Inertia for a solid cylindrical wheel is:  

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4 0
2 years ago
As light shines from air to water, the index of refraction is 1.02 and the angle of incidence is 38.0 °. What is the light's an
muminat

Answer:

Light's angle of refraction = 37.1° (Approx.)

Explanation:

Given:

Index of refraction = 1.02

Base of refraction = 1

Angle of incidence = 38°

Find:

Light's angle of refraction

Computation:

Using Snell's law;

Sin[Angle of incidence] / Sin[Light's angle of refraction] = Index of refraction / Base of refraction

Sin38 / Light's angle of refraction = 1.02 / 1

Sin[Light's angle of refraction] = Sin 38 / 1.02

Sin[Light's angle of refraction] = [0.6156] / 1.02

Sin[Light's angle of refraction] = 0.6035

Light's angle of refraction = 37.1° (Approx.)

5 0
3 years ago
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