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geniusboy [140]
3 years ago
5

An object of mass m 1 moving with speed v collides with another object of mass m 2 at rest and stick to it. Find the impulse to

the second object.
Physics
1 answer:
garri49 [273]3 years ago
8 0

Answer:

(m1+m2)vo=m1v+m2×0

⟹vo=m1+m2m1v

The impulse imparted to second object is equal to change is momentum is -

J=m2vo=m1+m2m2m1v

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4 years ago
A +26.3 uC charge qy is repelled by a force
Musya8 [376]

Answer:

+1.46×10¯⁶ C

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C

Force (F) = 0.615 N

Distance apart (r) = 0.750 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Charge 2 (q₂) =?

The value of the second charge can be obtained as follow:

F = Kq₁q₂ / r²

0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²

0.615 = 236700 × q₂ / 0.5625

Cross multiply

236700 × q₂ = 0.615 × 0.5625

Divide both side by 236700

q₂ = (0.615 × 0.5625) / 236700

q₂ = +1.46×10¯⁶ C

NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C

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3 years ago
A flywheel of mass 182 kg has an effective radius of 0.62 m (assume the mass is concentrated along a circumference located at th
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We know that

Kinectic energy= 1/2 mv^2 .............eqn(1)

This can be written in term of angular velocity, as

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Can a object have have zero velocity and nonzero acceleration?
vladimir1956 [14]

Answer:

yes

Explanation:

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