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svetlana [45]
3 years ago
13

An old-fashioned LP record rotates at 33 1/3 RPM

Physics
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

Part a) \frac{5}{9}\ \frac{rev}{sec}

Part b) \frac{9}{5}\ \frac{sec}{rev}

Explanation:

Part a) what is its frequency, in rev/s

we have that

An old-fashioned LP record rotates at 33 1/3 RPM

so

33\frac{1}{3}\ \frac{rev}{min}

Convert mixed number to an improper fraction

33\frac{1}{3}\ \frac{rev}{min}=\frac{33*3+1}{3}=\frac{100}{3}\ \frac{rev}{min}

Remember that

1\ min=60\ sec

Convert rev/min to rev/sec

\frac{100}{3}\ \frac{rev}{min}=\frac{100}{3}(\frac{1}{60})=\frac{100}{180}\ \frac{rev}{sec}

Simplify

\frac{5}{9}\ \frac{rev}{sec}

Part b) what is it period, in seconds

we know that

The period is the reciprocal of the frequency

therefore

the frequency is

\frac{9}{5}\ \frac{sec}{rev}

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Below

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(Picture below)

■■■■■■■■■■■■■■■■■■■■■■■■■■

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■■■■■■■■■■■■■■■■■■■■■■■■■■

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■■■■■■■■■■■■■■■■■■■■■■■■■■

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■■■■■■■■■■■■■■■■■■■■■■■■■■

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