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3 years ago

CN you help me with this question?

Physics

1 answer:

nata0808 [166]3 years ago

5 0

That period of time is called the "half-life" of that particular isotope,
because that's how long it takes for ONE-HALF of it to decay and
turn into some other substance.

So, however much you start out with, you can expect that after one
half-life of time has passed, half of the total amount (50%) has decayed
and turned into other substances, and the other half (50%) remains.

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Identify which gas had the greatest volume change.

Aleksandr-060686 [28]

Water and h20 delivery have been a very meaningful company to the community

6 0

3 years ago

A go-cart is traveling at a rate of 25 m/sec for 20 seconds. How far will the go cart travel?

notsponge [240]

Answer:

Distance travel by go-cart = 500 meter

Explanation:

Given:

Speed of go cart = 25 m/s

Time travel = 20 seconds

Find:

Distance travel by go-cart

Computation:

Distance = Speed x time

Distance travel by go-cart = Speed of go cart x Time travel

Distance travel by go-cart = 25 x 20

Distance travel by go-cart = 500 meter

4 0

3 years ago

A certain superconducting magnet in the form of a solenoid of length 0.300 m can generate a magnetic field of 8.90 T in its core

Ivan

Answer:

The number of turns in the solenoid is 22366.

Explanation:

The number of turns in the solenoid can be found using the following equation:

$B = \mu_{0} I\frac{N}{L}$

Where:

B: is the magnetic field = 8.90 T

L: is the solenoid's length = 0.300 m

N: is the number of turns =?

I: is the current = 95 A

μ₀: is the magnetic constant = 4π×10⁻⁷ H/m

By solving equation (1) for N we have:

$N = \frac{BL}{\mu_{0} I} = \frac{8.90 T*0.300 m}{4\pi \cdot 10^{-7} H/m*95 A} = 22366 turns$

Therefore, the number of turns in the solenoid is 22366.

I hope it helps you!

8 0

3 years ago

During each cycle, a refrigerator ejects 610 kJ of energy to a high-temperature reservoir, and takes in 505 kJ of energy from a

jenyasd209 [6]

Answer

A. the work done on the refrigerant in each cycle is 105kJ

B the coefficient of performance of the refrigerator is 4.8

Explanation

Given data

Work done at high temperature T2 Qh=610kJ

Work done at low temperature T1 Ql=505kJ

We know that the net work done by the refrigerator is expressed as

Wnet= Qh-Ql

=610-505

=105kJ

Also we know that the coefficient of performance is expressed as

COP= Ql/Wnet

COP= 505/105

= 4.8

8 0

3 years ago

On the kelvin scale what is the freezing point of water

Alla [95]

Freezing point of the water is known as 273 K

Hope this helps!

8 0

3 years ago