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luda_lava [24]
3 years ago
11

Ms. Peters drove from her home to the park

Mathematics
1 answer:
worty [1.4K]3 years ago
5 0

It takes 15 minutes for Ms. Peter to drive from park to her home

Given :

from her home to the park at an average speed of 30 miles per hour and

returned home along the same route at an average speed of 40 miles per hour

it takes 20 minutes to travel

Convert 20 minutes in to hour (divide by 60)

20 minutes = 1/3 hour

We know that distance = speed x time

 From home to park, distance  =speed \cdot time =30 \cdot \frac{1}{3} =10 miles

So , distance between home  and park is 10 miles

Now we calculate the time taken to return from park to home

time taken =\frac{distance}{speed} =\frac{10}{40}=\frac{1}{4}\\

Time taken is 1/4 hours. Convert it into minutes by multiplying by 60

\frac{1}{4} \cdot 60=15

So it takes 15 minutes for Ms. Peter to drive from park to her home

Learn more : brainly.com/question/18839247

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Soloha48 [4]

Answer:

Null hypothesis:\mu \leq 60  

Alternative hypothesis:\mu > 60  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{67-60}{\frac{12}{\sqrt{16}}}=2.33  

Step-by-step explanation:

Data given and notation  

\bar X=67 represent the sample mean    

s=12 represent the population standard deviation for the sample  

n=16 sample size  

\mu_o =60 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 60, the system of hypothesis would be:  

Null hypothesis:\mu \leq 60  

Alternative hypothesis:\mu > 60  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{67-60}{\frac{12}{\sqrt{16}}}=2.33  

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