Answer:
Issue the Dcdiag on all domain controller servers.
Explanation:
Active directory is a database that holds information of client's authentication for service access in a server. Domain controllers in servers holds these active directories, to replicate client's credentials for quick response to access to the server.
When a server domain can not contact the active directory domain controller, the Dcdiag command is issued on the server to check for connectivity issue to the DNS, AD replication, SYSVOL replication etc.
Answer:
A
Issues can lead reoccuring costomers to not want to come back, resulting in this issue.
The below displays ice-creams with its associated flavours. This we would display using <UL>
• Stick
o Chocobar
o Feast
• Bowl
o Butterscotch
o Blueberry
<UL>
<LI>Stick
<UL>
<LI>Chocobar </LI>
<LI> feast</LI>
</UL>
</LI>
<LI>Bowl
<UL>
<LI> Butterscotch </LI>
<LI> Blueberry </LI>
</UL>
</LI>
</UL>
Here <UL> tag is used to create un ordered list and one another <UL> tag inside <LI> created nested list which is the actual requirement. Like this we can created nested unordered lists and you can nest upto 4 levels and increasing the number of levels further may reduce clarity.
This issue will happen mostly if cellular network will not be down, or suppose if cellular network is down mostly, or it will be rainy or a current cutoff issue might be occurred.
<u>Explanation:</u>
The following step to be made for trouble shoot his phone when cellular network is down.
1. Restart the mobile:- After restarting kindly check mobile connectivity.
2. Check for mobile air plane mobile and make sure the mobile phone is not in air plane mode.
3. Check the income and outgoing vapidity.
4. Switch off the mobile, Remove service provider sim card from mobile and reinsert the sim card and start the mobile.
5. Still connectivity problem, either contact the service provider or replace with new sim card.
<span>#include <iostream>
using namespace std;
bool bears(int n);
int main(){
int number;
do{
cout<<"enter the amount of bears (press 0 to stop the program): ";
cin>>number;
if (bears(number)){
cout<<"you have reached the goal!"<<endl;
}
else{
cout<<"sorry, you have not reached the goal."<<endl;
}
}while(number != 0);
}
bool bears(int n){
if (n < 42){
return false;
}
else if (n == 42){
return true;
}
else{
if (n % 5 == 0){
return bears(n - 42);
}
else if(n % 2 == 0){
return bears(n / 2);
}
else if(n % 4 == 0|| n % 3 == 0)
{
int one;
int two;
one=n%10;
two=(n%100)/10;
return bears(n - one * two);
}
}
<span>}</span></span>
