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alexira [117]
3 years ago
10

Which statement about balanced chemical equations is true?

Chemistry
1 answer:
Inessa05 [86]3 years ago
4 0

O B. The total mass of the reactants equals the total mass of the

products.

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Highest ionization energy: Li, Be, B
Ad libitum [116K]

Hello!


On the periodic table, as we go down the periodic table, the ionization energy decreases, but as we go across the periodic table (left to right), the ionization increases.


On the periodic table, lithium (Li) is located in column one, beryllium (Be) is located in column two, and (B) boron is located in column 13. As stated above, when we go across the periodic table (left to right), the ionization increases.


Therefore, the element with the highest ionization energy is Boron, or symbol B on the period table.

3 0
4 years ago
In a physical change, the _____ does not change.
Ksivusya [100]

Physical changes occur when objects or substances undergo a change that does not change their chemical composition. This contrasts with the concept of chemical change in which the composition of a substance changes or one or more substances combine or break up to form new substances.

7 0
3 years ago
if an iron nail is placed in a glass of water the nail will sink. Is the density of iron smaller than or larger than the density
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5 0
3 years ago
50 POINTS*** Which of the following is not a correct chemical equation for a double displacement reaction?
hammer [34]
I mostly believe in between D and B beacuse K3po4 and caco3 is not an element equation

4 0
3 years ago
Read 2 more answers
Consider the chemical equations shown here.
vichka [17]

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Explanation:

The overall equation for the reaction that produces  P₄0₁₀ is :

P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

Now let us derive this equation:

Given equations:

   P₄_{s} + 30₂_{g}  ⇒ P₄0₆_{s}  equation 1;

   P₄_{s} + 50₂_{g} ⇒  P₄0₁₀_{s}  equation 2;

To get the overall combined equation, the equation 1 must be reversed and added to equation 2:

            P₄0₆_{s} ⇒ P₄_{s} + 30₂_{g}   equation 3

                      +

            equation 2:

 P₄_{s} + 50₂_{g}  +    P₄0₆_{s}  ⇒  P₄0₁₀_{s}  +  P₄_{s} + 30₂_{g}  

cancelling specie that appears on both sides and removing excess oxygen gas on the reactant side gives;

   

                  P₄0₆_{s} + 20₂_{g}   ⇒    P₄0₁₀_{s}

learn more:

Net equation brainly.com/question/2947744

#learnwithBrainly

5 0
3 years ago
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